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aliya0001 [1]
2 years ago
7

i need to find the zeros by factoring but im stuck plss help me i think the zeros may be 0, 1, -4, and 4 but i dont know how to

get them??

Mathematics
2 answers:
Sveta_85 [38]2 years ago
5 0
This should help you on how to get the zeros and the answer for the bottom question is A

Nana76 [90]2 years ago
3 0
In other terms, once factored, you can set each parenthesis equal to zero. So like for (x-1), you set to zero, and solve. This gives factors. If the x is outside of parenthesis, like the -4x, then there is a root of zero.

In this case. Factor by grouping, then you will have several parenthesis multiplied by each other. Set each to zero
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Bryce tried to solve an equation step by step. \qquad\begin{aligned} \dfrac83&=3\left(c+\dfrac53\right)\\\\ \\ \dfrac83&
sesenic [268]

Answer:

Bryce is wrong in step 1 because he did not distribute 3 over 5/3

Explanation

Given the steps taken by bryce as shown, we are to find where he made an error

\qquad\begin{aligned} \dfrac83&=3\left(c+\dfrac53\right)\\\\ \\ \dfrac83&=3c+\dfrac53&\green{\text{Step } 1}\\\\ \\ 1&=3c&\blue{\text{Step } 2}\\\\ \\ \dfrac13&=c&\purple{\text{Step } 3}\\\\ \end{aligned}

Given the expression;

\dfrac83&=3\left(c+\dfrac53\right)\\\\ \\

Step 1:Expand the bracket using the distributive law;

8/3 = 3c + 3(5/3)

<em>Simplify</em>

8/3 = 3c + 15/3

Step 2: Subtract 15/3 from both sides

8/3 - 15/3 = 3c+15/3-15/3

(8-15)/3 = 3c

-7/3 = 3c

Step 3: Multiply both sides by 1/3

-7/3 * 1/3 = 3c * 1/3

-7/9 = c

Swap

c = -7/9

From the calculation, we can see that Bryce is wrong in step 1 because he did not distribute 3 over 5/3 thereby making his solution incorrect

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Step-by-step explanation:

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Step-by-step explanation:

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Factor completely 4u^2-28u+49
aleksandrvk [35]

Assignment: \bold{Factor \ 4u^2-28u+49}

<><><><><>

Answer: \boxed{\bold{\left(2u-7\right)^2}}

<><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><>

[ Step One ] Rewrite \bold{4u^2-28u+49}

\bold{\left(2u\right)^2-2\cdot \:2u\cdot \:7+7^2}

[ Step Two ] Apply perfect square formula

Note: Perfect Square Formula: \bold{\left(a-b\right)^2=a^2-2ab+b^2}

\bold{a=2u,\:b=7}

\bold{\left(2u-7\right)^2}

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\bold{\rightarrow Rhythm \ Bot \leftarrow}

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Hi!

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