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aliya0001 [1]
2 years ago
7

i need to find the zeros by factoring but im stuck plss help me i think the zeros may be 0, 1, -4, and 4 but i dont know how to

get them??

Mathematics
2 answers:
Sveta_85 [38]2 years ago
5 0
This should help you on how to get the zeros and the answer for the bottom question is A

Nana76 [90]2 years ago
3 0
In other terms, once factored, you can set each parenthesis equal to zero. So like for (x-1), you set to zero, and solve. This gives factors. If the x is outside of parenthesis, like the -4x, then there is a root of zero.

In this case. Factor by grouping, then you will have several parenthesis multiplied by each other. Set each to zero
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Lynna [10]

Answer:

D

Step-by-step explanation:

A margin of error provides information on the  percentage points ones results will differ from the real value.

If margin of error is 3% and estimated value is 6%, it means that the confidence interval would be within ±3 of the estimated value.

So, the confidence interval would be between 3% (6% - 3%) and 9% (6% + 3%)

8 0
3 years ago
ill give brainliest!! Solve these equations for the variable. Check your solutions. please put the answers to this
yawa3891 [41]

Answer:

11. x=5

12. y= -1

13. m= -22

14. m=-4

15.n= 12, -4

16. x=6 ,-5

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Step-by-step explanation:

I hope this help ;-)

8 0
2 years ago
Which of the following (x,y) pairs is the solution for the system of equations x+2y=4 and -2x+y=7
kakasveta [241]

Answer:

(-2 ,3)

Step-by-step explanation:

Step 1: Rewrite first equation

x = 4 - 2y

-2x + y = 7

Step 2: Substitution

-2(4 - 2y) + y = 7

Step 3: Solve <em>y</em>

-8 + 4y + y = 7

-8 + 5y = 7

5y = 15

y = 3

Step 3: Plug in <em>y</em> to find <em>x</em>

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3 0
3 years ago
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77julia77 [94]

Answer:

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4 0
1 year ago
Find and simplify the difference quotient of the form<img src="https://tex.z-dn.net/?f=%5Cfra%5Cfrac%7Bf%28x%29-f%28a%29%7D%7Bx-
Ilia_Sergeevich [38]

Answer: 3x + 13

Step-by-step explanation:

f(x)=3x^2+x\\f(a)=3a^2+a\\f(4)=3*4^2+4=52\\\\f(x)-f(4)=3x^2+x-52=(x-4)(3x+13)\\\\\dfrac{f(x)-f(4)}{x-4} =\dfrac{3x^2+x-52}{x-4} \\\\if\ x \neq 4\ then \\\\\dfrac{f(x)-f(4)}{x-4} =\dfrac{(x-4)(3x+13)}{x-4} \\\\=3x+13\\

6 0
2 years ago
Read 2 more answers
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