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aliya0001 [1]
2 years ago
7

i need to find the zeros by factoring but im stuck plss help me i think the zeros may be 0, 1, -4, and 4 but i dont know how to

get them??

Mathematics
2 answers:
Sveta_85 [38]2 years ago
5 0
This should help you on how to get the zeros and the answer for the bottom question is A

Nana76 [90]2 years ago
3 0
In other terms, once factored, you can set each parenthesis equal to zero. So like for (x-1), you set to zero, and solve. This gives factors. If the x is outside of parenthesis, like the -4x, then there is a root of zero.

In this case. Factor by grouping, then you will have several parenthesis multiplied by each other. Set each to zero
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Use the figure to complete each statement<br> 1-6. pleaseee help will give brainliest
labwork [276]

Answer:

1. UW // TX

2. VX // UY

3. UW ≅ TY ≅ YX

4. YW = \frac{1}{2} TV

5. TX = 2 UW

6. ∠TXV ≅∠WUY

Step-by-step explanation:

The line segment joining the midpoint of two sides of a triangle is parallel to the third side and equal to half its length

In Δ XVT

∵ U is the midpoint of VT

∵ W is the midpoint of VX

∵ XT is the 3rd side of the triangle

→ By using the rule above

∴ UW // TX ⇒ (1)

∴ UW = \frac{1}{2} TX

→ Multiply both sides by 2

∴ 2 UW = TX

∴ TX = 2 UW ⇒ (5)

∵ Y is the midpoint of TX

∴ TY = YX = \frac{1}{2} TX

∵ UW = \frac{1}{2} TX

∴ UW ≅ TY ≅ YX ⇒ (3)

∵ U is the midpoint of VT

∵ Y is the midpoint of XT

∵ VX is the 3rd side of the triangle

→ By using the rule above

∴ UY // VX

∴ VX // UY ⇒ (2)

∴ UY = \frac{1}{2} VX

∵ W is the midpoint of VX

∵ Y is the midpoint of XT

∵ TV is the 3rd side of the triangle

→ By using the rule above

∴ YW // TV

∴ YW = \frac{1}{2} TV ⇒ (4)

∵ 2 Δs UYW and XVT

∵ UY = \frac{1}{2} XV

∵ YW = \frac{1}{2} VT

∵ WU = \frac{1}{2} TX

∴ \frac{UY}{XV} = \frac{UW}{VT} = \frac{WU}{TX} = \frac{1}{2}

→ By using the SSS postulate of similarity

∴ ∠TXV ≅∠WUY ⇒ (6)

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3 years ago
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Katyanochek1 [597]

Answer:

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b) the slope is 1/1 or just 1

Step-by-step explanation:

You can find slope (rise/run) by picking a point on the graph. For example on question a I chose the point (-2, 1) i then counted how far my run was, which is 2, and my rise (or how far down it went) was -1. Therefore my slope was 2/-1 or just -2.

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3 years ago
find an equation of the tangent plane to the given parametric surface at the specified point. x = u v, y = 2u2, z = u − v; (2, 2
Alexxandr [17]

The surface is parameterized by

\vec s(u,v) = x(u, v) \, \vec\imath + y(u, v) \, \vec\jmath + z(u, v)) \, \vec k

and the normal to the surface is given by the cross product of the partial derivatives of \vec s :

\vec n = \dfrac{\partial \vec s}{\partial u} \times \dfrac{\partial \vec s}{\partial v}

It looks like you're given

\begin{cases}x(u, v) = u + v\\y(u, v) = 2u^2\\z(u, v) = u - v\end{cases}

Then the normal vector is

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Now, the point (2, 2, 0) corresponds to u and v such that

\begin{cases}u + v = 2\\2u^2 = 2\\u - v = 0\end{cases}

and solving gives u = v = 1, so the normal vector at the point we care about is

\vec n = -4\,\vec\imath+2\,\vec\jmath-4\,\vec k

Then the equation of the tangent plane is

\left(-4\,\vec\imath + 2\,\vec\jmath - 4\,\vec k\right) \cdot \left((x-2)\,\vec\imath + (y-2)\,\vec\jmath +  (z-0)\,\vec k\right) = 0

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\boxed{2x - y + 2z = 2}

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2 years ago
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pochemuha

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Step-by-step explanation:

Right on edg.

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3 years ago
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