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Leona [35]
3 years ago
6

Use the equation and type the ordered-pairs.

Mathematics
2 answers:
s2008m [1.1K]3 years ago
6 0

Answer:

The given equation , in two variables is

   y= log 3 x

Ordered pair is written in the form of ,(x,y).

1. x=\frac{1}{3}, y=\log 3 \times\frac{1}{3}\\\\ y=\log 1 \\\\ y=0\\\\2. x=1, y=\log 3 \times 1\\\\y=\log 3\\\\ 3. x=3, y=\log 3 \times 3\\\\ y=\log 3^2\\\\ y=2\log 3\\\\4. x=9=3^2, y=\log 3 \times 9\\\\ y=\log 3^3\\\\ y=3\log 3 \\\\5.  x=27=3^3, y=\log 3 \times 3^3\\\\ y=\log 3^4\\\\ y=4\log 3\\\\6. x=81=3^4, y=\log 3 \times 3^4\\\\ y=\log 3^5\\\\ y=5\log 3

Sophie [7]3 years ago
3 0
If it is y = love 2x:

 <span>y = log_2 (x) =====> when x = 1/2 
y = log_2 (1/2) 
y = -1 ======> (1/2 , -1) 

y = log_2 (x) =====> when x = 1 
y = log_2 (1) 
y = 0 ======> (1 , 0) 

y = log_2 (x) =====> when x = 2 
y = log_2 (2) 
y = 1 ======> (2 , 1) 

y = log_2 (x) =====> when x = 4 
y = log_2 (4) 
y = 2 ======> (4 , 2) 

y = log_2 (x) =====> when x = 8 
y = log_2 (8) 
y = 3 ======> (8 , 3) 

y = log_2 (x) =====> when x = 16 
y = log_2 (16) 
y = 4 ======> (16 , 4) </span>
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What value of x satisfies the equation 5x+1.5=7
Arte-miy333 [17]
First thing we are going to do to solve this is to subtract 1.5 from both sides so:
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Answer:

hope this helps

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