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aleksklad [387]
2 years ago
6

Is there any Indian active right now?​

Mathematics
1 answer:
Vera_Pavlovna [14]2 years ago
7 0

Answer:

do see the photos

stay safe po

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HELP ASAP DUE TODAY IT IS EASY IM JUST TOO LAZY IM SO SORRY
ankoles [38]

Answer:

B. Mean absolute deviation

Step-by-step explanation:

The mean absolute deviation of a dataset is the average distance between each data point and the mean.

8 0
3 years ago
Write the equation in standard form using integers.
disa [49]
The Answer is: 2x+3y=-15
4 0
3 years ago
Suppose X and Y have joint density f(x,y)=1 for 0
SashulF [63]

∫¹₀ min (1, n/y)dy = ∫ⁿ₀ (1, n/y)dn + ∫¹n min (1, n/y) dy

Hope this helps


8 0
3 years ago
Una recta con pendiente -2 ´pasa por el punto P(5, -1). La abscisa del punto Q que está en esa recta es 1. Encuentre la ordenada
oksian1 [2.3K]

Answer:

La ordenada de Q es 7.

Step-by-step explanation:

La ecuación de una recta es:

y = a*x + b

donde a es la pendiente y b es la ordenada al origen.

Para este problema, sabemos que la pendiente es -2

Entonces:

a = -2

y = -2*x + b

También sabemos que esta recta pasa por el punto (5, -1)

Esto significa que cuando evaluamos la ecuación en x = 5, y toma el valor y = -1

Si reemplazamos esos valores en la ecuación, obtenemos:

-1 = -2*5 + b

-1 = -10 + b

-1 + 10 = b

9 = b

Entonces la ecuación de la recta es:

y = -2*x + 9

Sabemos que el punto Q está en la línea, y la abscisa de este punto es 1.

Entonces este punto es Q (1, k)

donde k es la ordenada de este punto.

Porque nuestra línea también pasa por este punto, podemos concluir que cuando x = 1, y = k

Reemplazando eso en la ecuación tenemos:

k = -2*1 + 9 = -2 + 9 = 7

k = 7

La ordenada de Q es 7.

7 0
3 years ago
HELP PLS!!!! IM GONNA GIVE YOU THE BRANLIEST ANSWER!!!
djverab [1.8K]

Answer:

25

Step-by-step explanation:

By counting the height ( frequency ) of each block and adding gives the number of students in total

20 - 24 → 5

24 - 28 → 6

28 - 32 → 5

32 - 36 → 2

36 - 40 → 7

Total = 5 + 6 + 5 + 2 + 7 = 25

4 0
3 years ago
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