8988989889 IDK hate doing the it but luv getting the answers
Assume that the length of the rectangle is "l" and that the width is "w".
We are given that:
(1) The length is one more than twice the base. This means that:
l = 2w + 1 .......> equation I
(2) The perimeter is 92 cm. This means that:
92 = 2(l+w) ...........> equation II
Substitute with equation I in equation II to get the width as follows:
92 = 2(l+w)
92 = 2(2w+1+w)
92/2 = 3w + 1
46 = 3w + 1
3w = 46-1 = 45
w = 45/3
w = 15
Substitute with w in equation I to get the length as follows:
l = 2w + 1
l = 2(15) + 1
l = 30 + 1 = 31
Based on the above calculations:
length of base = 31 cm
width of base = 15 cm
I don't know vrghhhhhhhhhhhh
Answer:
B, A
Step-by-step explanation:
In the first equation, if an unknown number plus 17 equals 66, then what step would you take?
For example, if an unknown number plus 2 equaled 3, then you would know that number is 1, right? What steps did you take to get that? You subtracted 2 from both sides.
In this example, if x + 17 = 66, then subtracting 17 from both sides gets us x = 49.
The same applies for the second example. If x minus 54 equals 125, then you would add 54 to get x = 179.
Answer:
w+w
Step-by-step explanation:
