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denpristay [2]
3 years ago
13

An equation is shown below. 12 – 6(w – 3) = 3(– 5 – 3w) + 21 Enter the solution of w for this equation.

Mathematics
1 answer:
gogolik [260]3 years ago
5 0
<span>Simplifying
12 + -6(w + -3) = 3(-5 + -3w) + 21

Reorder the terms:
12 + -6(-3 + w) = 3(-5 + -3w) + 21
12 + (-3 * -6 + w * -6) = 3(-5 + -3w) + 21
12 + (18 + -6w) = 3(-5 + -3w) + 21

Combine like terms: 12 + 18 = 30
30 + -6w = 3(-5 + -3w) + 21
30 + -6w = (-5 * 3 + -3w * 3) + 21
30 + -6w = (-15 + -9w) + 21

Reorder the terms:
30 + -6w = -15 + 21 + -9w

Combine like terms: -15 + 21 = 6
30 + -6w = 6 + -9w

Solving
30 + -6w = 6 + -9w

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '9w' to each side of the equation.
30 + -6w + 9w = 6 + -9w + 9w

Combine like terms: -6w + 9w = 3w
30 + 3w = 6 + -9w + 9w

Combine like terms: -9w + 9w = 0
30 + 3w = 6 + 0
30 + 3w = 6

Add '-30' to each side of the equation.
30 + -30 + 3w = 6 + -30

Combine like terms: 30 + -30 = 0
0 + 3w = 6 + -30
3w = 6 + -30

Combine like terms: 6 + -30 = -24
3w = -24

Divide each side by '3'.
w = -8

Simplifying
w = -8</span>
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Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p
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Answer:

Colin has <em>8 sheets </em>left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = x

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8

So, the answer is:

Colin has <em>8</em> <em>sheets </em>left for his third class.

5 0
3 years ago
Solve the system of equations using the substitution method. 2x+8y=4 x=−3y+5
goldenfox [79]
Since x=-3y+5, substitute x for -3y+5. 

2(-3y+5)+8y=4

Distribute. 

-6y+10+8y= 4

2y+10= 4

Subtract 10 on both sides. 

2y=-6

Divide by 2.

y=-3

Plug in y=-3. 

x=-3(-3)+5
x= 9+5
x=14

(14,-3)

We can check this. 

2(14)+8(-3)=4
28-24=4
4=4 <== this works

I hope this helps!
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3 years ago
In PE class, Josiah and his friends had to measure their heights. They each
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Answer:

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Step-by-step explanation:

3 1/2 = 1 yard and 1/2 inch then a yard then 31 divided by 12 is 2.??

6 0
3 years ago
Cesar, Carmen, and Dalila raised $95.34 for their tennis team. Carmen raised $12.12 less than Cesar, and Cesar raised $35 more t
NeTakaya

Answer:

Cesar's amount can be expressed by x + 12.12

Dalila's amount can be expressed as  x - 22.88

Step-by-step explanation:

If Carmen raised 12.12.less than Cesar, that means his amount is 12.12 more than hers so that is <u>x + 12.12</u> for <u>Cesar</u>.

If  Cesar raised 35 more than Dalila, her amount is Cesar's minus 35. Calculate: x+12.12 - 35. the difference is 22.88 less than x  so the amount for <u>Dalila is x- 22.88</u>

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