Answer:
sinΘ = 
Step-by-step explanation:
using the identity
sin²x + cos²x = 1 ( subtract cos²x from both sides )
sin²x = 1 - cos²x ( take square root of both sides )
sinx = ± 
given
cosΘ = -
, then
sinΘ = ± 
= ± 
= ± 
= ± 
since Θ is in quadrant II where sinΘ > 0 , then
sinΘ = 
Answer:
Step-by-step explanation:
oh boy
1) 9 < 16
2) -4 < 5
3) 18 > -19
4) -38 < -16
5) 6 > 4
6) -14 > -25
7) -45 > -55
8) -2 > -10
9) -4, -1, 1, 3, 6
10) -15, -13, -5, 8
11) -9, -6, -5, -1, 0
12) -4, -2, 1, 3
13) -10, -9, 7, 8, 11
14) -33, -25, -14, -4, 7
hope this helps <3
ANSWER
The solution is 
EXPLANATION
We want to solve the simultaneous equations

and
.
We substitute equation (2) in to equation (1), to obtain

This has now become a linear equation in a single variable
.
We solve for x by grouping like terms.


We divide through by negative 3 to get;
.
Hence, the solution is 
Answer:
17
Step-by-step explanation:
4(3) + 5 = ?
12 + 5 = 17