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3 years ago

Can someone help me answer

Mathematics

2 answers:

Ronch [10]3 years ago

7 0

She needs to buy 9 juice bottle

Ilya [14]3 years ago

3 0

Answer: she should by 9 bottles of juice

Step-by-step explanation:

because there's 2 L per one bottle, 2L (X bottles) = 18L, X = 9

You might be interested in

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°

Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = $c^{2}$ = $a^{2} + b^{2}$

a = 7 and b = 11

$a^{2}$ = 49

$b^{2}$ = 121

Plugging in the values, we will get:

$c^{2}$ = 49 + 121

$c^{2}$ = 170

c = $\sqrt{170}$

To calculate the unknown angle B, we can use law of sine.

Law of sine = $\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$

So,

$\frac{c}{sinC}$ = $\frac{b}{sinB}$

$\frac{\sqrt{170} }{sin90}$ = $\frac{11}{sinB}$

Sin90 = 1

sinB = $\frac{11}{\sqrt{170} }$

B = $sin^{-1}$ ( $\frac{11}{\sqrt{170} }$ )

B = 57.5°

8 0

3 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

3 years ago

Does anyone get this?

stepladder [879]

Answer: B

Step-by-step explanation:

In the systems of equation it already gives you the solution for x which is -2 so all you have to do is substitute -2 into the first equation and solve for y.

y= 2/3x + 3

x= -2

Substitute x for -2

y = $\frac{2}{3}* \frac{-2}1} + 3$

y= $\frac{-4}{3}$ + $\frac{3}{1}$

y = $\frac{5}{3}$

so now you have the solution like this $(-2,\frac{5}{3})$

8 0

3 years ago

The school that Brenda goes to is selling tickets to the annual talent show. On the first day of the ticket sales the school sol

KiRa [710]

A=cost er adult ticket
c=cost per child ticket

2a+14c=96
12a+8c=120

solve

simplify by dividing firs equation by 2 and 2nd by 4

a+7c=48
3a+2c=30

multiply first equaiton by -3 and add to second
-3a-21c=-144
3a+2c=30 +
0a-19c=-114

-19c=-114
divide both sides by -19
x=6

sub back

a+7c=48
6+7c=48
minus 6
7c=42
divide 7
c=6

adult ticket=$6
child ticekt=$6

7 0

3 years ago

Question 6(Multiple Choice Worth 1 points) (06.01 LC) Choose the correct classification of 5x + 2x2 − 8 by number of terms and b

Yakvenalex [24]

Question 7: Choose the correct simplification of the expression (3x − 6)(2x2 − 4x − 5)

Answer:

7. 6x³ - 12x² + 12x + 15

Step-by-step explanation:

(3x-6)(2x² - 4x - 5)

3x • 2x² = 6x³

3x • -4x = -12x²

3x • -5 = -15

-6 • 2x² = -12x²

-6 • -4x = 24x

-6 • -5 = 30

combine terms

6x³ - 12x² - 15 - 12x² + 24x + 30

combine like terms

6x³ - 24x² + 24x + 15

hope this helps :)

in the future, only ask one question per brainly submission. thanks!

7 0

3 years ago