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Amanda [17]
3 years ago
13

Can someone help me answer

Mathematics
2 answers:
Ronch [10]3 years ago
7 0
She needs to buy 9 juice bottle
Ilya [14]3 years ago
3 0

Answer: she should by 9 bottles of juice

Step-by-step explanation:

because there's 2 L per one bottle, 2L (X bottles) = 18L, X = 9

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The 3-year loan is cheaper overall.

The 3-year loan’s monthly payment would be higher.

The 5-year loan, is more expensive overall.

The 5-year loan’s monthly payment would be lower.

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valkas [14]
The slope for the line is 3/4
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Nata [24]

C.

he starts 6500 ft up do that's the b in y=mx+b.

the m is -250 because that's the rate, and it's negative because he's going down.

4 0
3 years ago
Which of the following are solutions to the equation below 3x^2+27x+54=0
VikaD [51]

Answer:x=6

Step-by-step explanation:Step-1 : Multiply the coefficient of the first term by the constant 1 • 18 = 18

Step-2 : Find two factors of 18 whose sum equals the coefficient of the middle term, which is -9 .

-18 + -1 = -19

-9 + -2 = -11

-6 + -3 = -9 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -6 and -3

x2 - 6x - 3x - 18

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-6)

Add up the last 2 terms, pulling out common factors :

3 • (x-6)

Step-5 : Add up the four terms of step 4 :

(x-3) • (x-6)

Which is the desired factorization

7 0
3 years ago
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Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b
jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that  R should represent the set of all possible outcomes generated from  a bit string of length 10 .

So; as each place is fitted with either 0 or 1

\mathbf{|R|= 2^{10}}

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if  a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

\mathbf{P(E) = \dfrac{|E|}{|R|}}

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

\mathbf{{|E|}=1 }   ; \mathbf{|R|= 2^{10}}

\mathbf{P(E) = \dfrac{1}{2^{10}}}

4 0
3 years ago
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