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Mathematics

2 answers:

DiKsa [7]3 years ago

4 0

Answer:

I would go option a

Step-by-step explanation:

vodka [1.7K]3 years ago

4 0

<h3>Answer:</h3>

Option 2

<h3>Step-by-step explanation:</h3>

Option 2 is better because for option one after 15 years your going up $7500 and with option 2 your going up 14062.5 in 15 years.

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Is the initial depth 3 inches?

hichkok12 [17]

Answer:

yes

Step-by-step explanation:

i just answered this question lol

6 0

3 years ago

Max and Emma are discussing their math homework and disagree on the answer for one question. Max says that integers are closed u

hram777 [196]

A set has closure under an operation if performance of that operation on members of the set always produces a member of the same set; in this case we also say that the set is closed under the operation.

A closure property is a certain rule that holds <u>if it is true for all elements of a set under the given operation</u> and a closure property does not hold <u>if there is at least one pair of elements that do not follow the closure property under the given operation.</u>

Therefore, Emma is correct, because you can find a counterexample (7:2=3.5) that gives you a non-integer answer.

Answer: correct option is B

4 0

3 years ago

If we sample from a small finite population without replacement, the binomial distribution should not be used because the event

seropon [69]

Answer:

5/4324 = 0.001156337

Step-by-step explanation:

To better understand the hyper-geometric distribution consider the following example:

There are 100 senators in the US Congress, and suppose 60 of them are republicans so 100 - 60 = 40 are democrats).

We extract a random sample of 30 senators and we want to answer this question:

What is the probability that 10 senators in the sample are republicans (and of course, 30 - 10 = 20 democrats)?

The answer using the h-g distribution is:

$\large \frac{\binom{60}{10}\binom{100-60}{30-10}}{\binom{100}{30}}=\frac{\binom{60}{10}\binom{40}{20}}{\binom{100}{30}}$

Now, imagine there are 56 senators (56 lottery numbers), 6 are republicans (6 winning numbers and 50 losers), we extract a sample of 6 senators (the bettor selects 6 numbers). What is the probability that 4 senators are republicans? (What is the probability that 4 numbers are winners?).

<em>As we see, the situation is exactly the same,</em> but changing the numbers. So the answer would be

$\large \frac{\binom{6}{4}\binom{56-6}{6-4}}{\binom{56}{6}}=\frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}$