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2 years ago

Ty in advance god bless

Mathematics

2 answers:

Sergio [31]2 years ago

7 0

The slope is -7/4 so it is B. In the graph it shows it.

damaskus [11]2 years ago

6 0

Step-by-step explanation:

3/7y + 3/4x = 3/5

y = -3/4x.7/3 +3/5.7/3

y = -7/4x +7/5

so the slope is -7/4

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the total cost for two items is $19 is the difference in the cost of the two items is $5 find the cost of each item.

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2 years ago

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In parallelogram ABCD, AD = 12 in, m∠C = 46º, m∠DBA = 72º. Find the area of ABCD

dmitriy555 [2]

Answer:

The area of parallelogram ABCD is $78.42 \mathrm{in}^{2}$

Explanation:

Given:

AD = 12 in

$m \angle C=46^{\circ}$

$m \angle D B A=72^{\circ}$

To Find:

The area of parallelogram ABCD=?

Solution:

When we construct the parallelogram with the given data, we get a parallelogram formed by 12 cm as one side and an angle with 46 degrees.

The area of the parallelogram can be calculated by $a b * \sin (a n g l e)$

Substituting the value of a=12 we have

$\text { Area of parallelogram }=12 * \text { bsin } 46$

<u>To find the value of b, </u>

We know that area of a triangle can be expressed as,

$\text { Area of triangle }=(A b / 2) \sin (\text {angle})$

So,

$(12 * B D / 2) * \sin 46=(A B * B D / 2) * \sin 72$

Cancelling BD and 2 on both sides we get,

$12 * \sin 46=A B * \sin 72$

$A B=12 * \frac{\sin 46}{\sin 72}$

Therefore,

$b=\frac{12 \sin 46}{\sin 72}$

Substituting the value of b,

$=12 *\left(\frac{12 \sin 46}{\sin 72}\right) * \sin 46$

=78.42

So the area of the parallelogram is $78.42 \mathrm{in}^{2}$

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3 years ago

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What is the area of a sector in a circle of radius 8cm,if the angle between the radii is 30°

IceJOKER [234]

Answer:

16.75 square cm

Step-by-step explanation:

$Area \: of \: sector = \frac{ \theta}{360 \degree} \times \pi {r}^{2} \\ \\ = \frac{30 \degree}{360 \degree} \times 3.14 \times {8}^{2} \\ \\ = \frac{1}{12} \times 3.14 \times 64 \\ \\ = \frac{1}{3} \times 3.14 \times 16 \\ \\ = \frac{1}{3} \times 50.24 \\ \\ = 16.7466667 \\ \\Area \: of \: sector = 16.75 \: {cm}^{2}$