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3 years ago

5

What is 8/9 / 2/3? . . . . .

2 answers:

svetoff [14.1K]3 years ago

7 0

Answer:

$1\frac{1}{3}$

Step-by-step explanation:·

$\frac{8}{9} x \frac{2}{3} \\= \frac{24}{18} \\\\\frac{24 / 6}{18 / 6} \\= \frac{4}{3} = 1\frac{1}{3}$

Semmy [17]3 years ago

4 0

Answer:

1 1/3

Step-by-step explanation:

keep change flip

8/9 x 3/2 = 24/18

24/18 = 1 1/3

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Please help with these two math questions!!!

Aleksandr [31]

Answer:

&

Step-by-step explanation:

12.) If one ticket is $9.50, and 879,575 tickets were sold, the two need to be multiplied. 9.5 * 879,575 = 8355962.50

So the total profit was $8,355,962.50

If each theater made an equal profit of that total, then just divide it by 755, but if that's not the case, then don't do that.

13.) If the boat can carry 582 passengers, and 13,105 people had ridden the first boat, then you have to divide the number of people riding the boat by the passenger count to determine the amount of trips made.

13,105 / 582 is 22.5, but you can round it to 23, because half of a trip isn't going to be made. I'm not entirely sure when the second question means, so... sorry, can't answer that one.

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4 0

3 years ago

Read 2 more answers

Bad gums may mean a bad heart. Researchers discovered that 79% of people who have suffered a heart attack had periodontal diseas

zysi [14]

Answer:

(A) 0.297

(B) 0.595

Step-by-step explanation:

Let,

H = a person who suffered from a heart attack

G = a person has the periodontal disease.

Given:

P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15

Compute the probability that a person has the periodontal disease as follows:

$P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.15)+(0.33\times(1-0.15))\\=0.399$

(A)

The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

$P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.15}{0.399} \\=0.29699\\\approx0.297$

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.

(B)

Now if the probability of a person having a heart attack is, P (H) = 0.38.

Compute the probability that a person has the periodontal disease as follows:

$P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.38)+(0.33\times(1-0.38))\\=0.5048$

Compute the probability of a person having a heart attack given that he or she has the disease:

$P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.38}{0.5048}\\ =0.59469\\\approx0.595$

The probability of a person having a heart attack given that he or she has the disease is 0.595.

4 0

3 years ago

Draw a flow diagram to indicate the different phases in reproduction.

8090 [49]

Answer:

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3 years ago

What is the formula for the area of a sector?

Assoli18 [71]

Answer: A = N/360 x (pi x r^2).

Step-by-step explanation:

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4 years ago

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Lacey traded U.S. dollars for Thai baht at an exchange rate of 1 U.S. dollar= 33.1898 Thai baht. She gave the exchanger a total

Rudik [331]

The answer is C. 38,168.27.

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3 years ago

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