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julsineya [31]
2 years ago
13

The grass is the number of gallons of white paint that were mixed with gallons of blue paint and various different ratios the nu

mber of gallons of white paint mix with 1 gallon of blue paint is ____
numerical answers expected

Mathematics
2 answers:
OverLord2011 [107]2 years ago
8 0
The slope/ratio is 2/1
So the ratio between white paint (1 gallon) is blue paint (1/2 gallons)

Answer : 1/2
miss Akunina [59]2 years ago
3 0
Person above is correct 1/2
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lukranit [14]

Answer:

1780 is the best answer

Step-by-step explanation:

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2 years ago
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A genetic experiment involving peas yielded one sample of offspring consisting of 437437 green peas and 129129 yellow peas. Use
navik [9.2K]

Answer:

The null hypothesis: \mathbf{H_o: p=0.27}

The alternative hypothesis: \mathbf{H_1: p \neq 0.27}

Test statistics : z = −2.30

P-value:  = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and  conclude that under the same​ circumstances the proportion of offspring peas will be yellow is not equal to 0.27

Step-by-step explanation:

From the given information:

Let's state the null and the alternative hypothesis;

Since The claim is that 27%  of the offspring peas will be yellow.

The null hypothesis state that the proportion of offspring peas will be yellow is equal to 0.27.

i.e

\mathbf{H_o: p=0.27}

The alternative hypothesis  state that the proportion of offspring peas will be yellow is not equal to 0.27

\mathbf{H_1: p \neq 0.27}

<u>The test statistics:</u>

we are given 437 green peas and 129 yellow apples;

Hence;

\hat p = \dfrac{x}{n}

where ;

\hat p = sample proportion

x = number of success

n = total number of the sample size

\hat p = \dfrac{129}{437+129}

\hat p = \dfrac{129}{566}

\mathbf{\hat p = 0.2279}

Now; the test statistics can be computed as :

z = \dfrac { \hat p -p }{\sqrt {\dfrac{p(1-p)}{n}  } }

z = \dfrac {0.2279 -0.27 }{\sqrt {\dfrac{0.27(1-0.27)}{566}  } }

z = \dfrac {-0.043 }{\sqrt {\dfrac{0.27(0.73)}{566}  } }

z = \dfrac {-0.043 }{\sqrt {\dfrac{0.1971}{566}  } }

z = \dfrac {-0.043 }{\sqrt {3.48233216*10^{-4} } }

z = \dfrac {-0.043 }{0.01866} }

z = −2.30

C. P-value

P-value = P(Z < z)

P-value = P(Z< -2.30)

By using the ​ P-value method and the normal distribution as an approximation to the binomial distribution.

from the table of standard normal distribution

move left until the first column is reached. Note the value as –2.0

move upward until the top row is reached. Note the value as 0.30

find the probability value as 0.010724 by the intersection of the row and column values gives the area to the left of

z = -2.30

P- value = 2P(z ≤ -2.30)

P-value = 2 × 0.01072

P - value = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and  conclude that under the same​ circumstances the proportion of offspring peas will be yellow is not equal to 0.27

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3 years ago
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30 divided by 6 is 5
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Rodrigo is helping make mashed potatoes for Thanksgiving. He plans to add 4 fluid ounces of heavy cream to his potatoes. If he b
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copy the given expression on your answer sheet

4 0
2 years ago
The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price
likoan [24]

Answer:

A)  3%

B)  Product A

Step-by-step explanation:

<u>Exponential Function</u>

General form of an exponential function: y=ab^x

where:

  • a is the initial value (y-intercept)
  • b is the base (growth/decay factor) in decimal form
  • x is the independent variable
  • y is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

<u>Part A</u>

<u>Product A</u>

Assuming the function for Product A is <u>exponential</u>:

f(x) = 0.69(1.03)^x

The base (b) is 1.03.  As b > 1 then it is an <u>increasing function</u>.

To calculate the percentage increase/decrease, subtract 1 from the base:

⇒ 1.03 - 1 = 0.03 = 3%

Therefore, <u>product A is increasing by 3% each year.</u>

<u>Part B</u>

\sf percentage\:change=\dfrac{final\:value-initial\:value}{initial\:value} \times 100

To calculate the percentage change in Product B, use the percentage change formula with two consecutive values of f(t) from the given table:

\implies \sf percentage\:change=\dfrac{10201-10100}{10100}\times 100=1\%

Check using different two consecutive values of f(t):

\implies \sf percentage\:change=\dfrac{10303.01-10201}{10201}\times 100=1\%

Therefore, as 3% > 1%, <u>Product A recorded a greater percentage change</u> in price over the previous year.

Although the question has not asked, we can use the given information to easily create an exponential function for Product B.

Given:

  • a = 10,100
  • b = 1.01
  • n = t - 1 (as the initial value is for t = 1 not t = 0)

\implies f(t) = 10100(1.01)^{t-1}

To check this, substitute the values of t for 1 through 4 into the found function:

\implies f(1) = 10100(1.01)^{1-1}=10100

\implies f(2) = 10100(1.01)^{2-1}=10201

\implies f(3) = 10100(1.01)^{3-1}=10303.01

\implies f(4) = 10100(1.01)^{4-1}=10406.04

As these values match the values in the given table, this confirms that the found function for Product B is correct and that <u>Product B increases by 1% per year.</u>

4 0
2 years ago
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