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julsineya [31]
2 years ago
13

The grass is the number of gallons of white paint that were mixed with gallons of blue paint and various different ratios the nu

mber of gallons of white paint mix with 1 gallon of blue paint is ____
numerical answers expected

Mathematics
2 answers:
OverLord2011 [107]2 years ago
8 0
The slope/ratio is 2/1
So the ratio between white paint (1 gallon) is blue paint (1/2 gallons)

Answer : 1/2
miss Akunina [59]2 years ago
3 0
Person above is correct 1/2
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(-7/8)(-3/4)<br><br>A:6/7<br><br>B:-21/32<br><br>C:21/32
Alekssandra [29.7K]
The answer is C
I pretty sure
7 0
3 years ago
Read 2 more answers
in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)
Nimfa-mama [501]

Answer:

The component of \vec u orthogonal to \vec a is \vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right).

Step-by-step explanation:

Let \vec u and \vec a, from Linear Algebra we get that component of \vec u parallel to \vec a by using this formula:

\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a (Eq. 1)

Where \|\vec a\| is the norm of \vec a, which is equal to \|\vec a\| = \sqrt{\vec a\bullet \vec a}. (Eq. 2)

If we know that \vec u =(2,1,1,2) and \vec a=(4,-4,2,-2), then we get that vector component of \vec u parallel to \vec a is:

\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)

\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)

\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)

Lastly, we find the vector component of \vec u orthogonal to \vec a by applying this vector sum identity:

\vec  u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a} (Eq. 3)

If we get that \vec u =(2,1,1,2) and \vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right), the vector component of \vec u is:

\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10}    \right)

\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)

The component of \vec u orthogonal to \vec a is \vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right).

4 0
3 years ago
Solve 63 minus X equals 62 for x
r-ruslan [8.4K]

Answer:

x=1

Step-by-step explanation:

This stuff is quite easy in reality. Here's a little example including your numbers.

63-x=62; solve for x\\\\63-x-63=62-63\\\\-x=1\\

by this point we are left with simplifying it. Since it's a double negative we get a positive. Thus x=1

5 0
3 years ago
F(x)=x^2+9<br> find complex zeros
Katen [24]
X=3i,-3i ;) used calculator to check
5 0
2 years ago
Vicente and Carla each ran 8 laps around
Marat540 [252]

Carla would have 4 laps left

Vincent ran 1.5 times faster than Carla

Carla is running half as slow as Vincent

So, the miles Carla would have covered would be half the miles covered by Vincent

Miles Carla would have covered when Vincente finishes his race =

8 / 2 = 4 laps

A similar question was solved here: brainly.com/question/4053690?referrer=searchResults

Number of laps remaining for Carla to run = 8 - 4 = 4 laps

3 0
2 years ago
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