Sample space = {p, r, o, b, a, b, i, l, I, t, y} = 11 possible outcomes
1sr event: drawing an I ( there are 2 I); P(1st I) = 2/11
2nd event drawing also an i: This is a conditional probability, since one I has already been selected the remaining number of I is now 1, but also the sample space from previously 11 outcome has now 10 outcomes (one letter selected and not replaced)
2nd event : P(also one I) = 1/10
P(selecting one I AND another I) is 2/11 x 1/10
P(selecting one I AND another I) =2/110 = 0.018
Step-by-step explanation:
ur gonna go 6 to the left and 5 up
Answer:
The correct option is SSS (Side-Side-Side) Theorem
Step-by-step explanation:
The question is incomplete because the diagrams of ΔLON and ΔLMN are not given. I have attached the diagram of both triangles below for better understanding of the question.
Consider the diagram attached below. We have to find the congruence theorem which can be used to prove that ΔLON ≅ ΔLMN
We can see in the diagram that both triangle have a common side that is LN. It means 1 side of both triangles is congruent because LN≅LN
Consider the sides ON and MN. Both side have a single bar on them, which means that it is given that both of these side are congruent. Hence ON≅MN
Consider the sides LO and LM. Both side have a double bars on them, which means that it is given that both of these side are also congruent. Hence LO≅LM
SSS theorem states that if all sides of the triangles are congruent, then the triangles themselves are also congruent, which is the same case in this question
Your answer is going to be c
Answer:
Ex) Julie has twice as many apples as Henry. If Julie has 15 apples how many does Henry have? 15 x 2 = 30 Henry has 30 apples.
Step-by-step explanation:
Look at the words around it, find out what numbers you are working with, and multiply.