Answer:
Step-by-step explanation:
Given that,
Cells are divided into two cell every 20mins, this implies that the half-life is 20mins
Initial population growth is 60cells
Growth rate r?
Population growth is modeled as
P(t) = Po•exp(rt)
Where,
Po is the initial growth at t= 0
Po= 60
P(t) is population at any time t.
Since the population doubles every 20mins(⅓hr)
Then, P(⅓) = 2×60 =120
Then, P(t) = 120cells
So, applying the formula
P(t) = Po•exp(rt)
120 = 60•exp(⅓r)
120/60 = exp(r/3)
2 = exp(r/3)
Take In of both sides
In(2) = r/3
Cross multiply
r = 3In(2)
r = 2.079 /hour
The growth rate is 2.079/hour.
Answer:

Step-by-step explanation:

Answer:
1.7 × 10⁻⁴
Step-by-step explanation:
The question relates to a two sample z-test for the comparison between the means of the two samples
The null hypothesis is H₀: μ₁ ≤ μ₂
The alternative hypothesis is Hₐ: μ₁ > μ₂

Where;
= 13.5
= 12
σ₁ = 2.5
σ₂ = 1.5
We set our α level at 0.05
Therefore, our critical z = ± 1.96
For n₁ = n₂ = 23, we have;

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96
Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983
Therefore;
The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.
Answer:
C. 5
Step-by-step explanation:
first expression 5 × (9-3) = 30
second one 45 - 3x
to make it 30 = 30
x should be = 5
Answer:
Step-by-step explanation: