Answer:
a) Number of hours it takes 1 centimetre of snow to form in Harper's yard = (1/5) hour = 0.20 hour
b) Centimetres of snow that accumulate per hour = 5 cm
Step-by-step explanation:
Complete Question
We can calculate the depth d of snow, in centimeters, that accumulates in Harper's yard during the first h hours of a snowstorm using the equation d=5h.
a) How many hours does it take for 1 centimeter of snow to accumulate in Harper's yard? hours
b) How many centimeters of snow accumulate per hour? centimeters
Solution
The depth of snow, d, in centimetres that accumulates in Harper's yard in h hours is given d = 5h
a) Number of hours it takes 1 centimetre of snow to form in Harper's yard.
d = 5h
d = 1 cm
h = ?
1 = 5h
h = (1/5) = 0.20 hour
b) Centimetres of snow that accumulate per hour.
d = 5h
In 1 hour, h = 1 hour
d = ?
d = 5 × 1 = 5 cm
Hope this Helps!!!
Answer: 258 yards
Step-by-step explanation:
Since Chad wants each balloon string to be 6 feet long, and Chad wants to get 43 balloons, the number of yards of string that he will need will be calculated by multiplying 43 by 6. This will be:
= 43 × 6
= 258 yards of string
Answer:
30°
Step-by-step explanation:
Answer:
9.4 secs
Step-by-step explanation:
From Newton's law of cooling;
T(t) = Ts + Do e^-kt
Where;
D0= initial temperature difference
Ts= Temperature of the surroundings
t= time
K = positive constant
Do = 185 - 60 = 125 degrees
167 = 60 + 125 e^-3k
167 - 60 = 125 e^-3k
107/125 = e^-3k
ln(e^-3k) = ln(107/125)
-3k = -0.1555
k = 0.1555/3
k = 0.0518
Substituting the value of k to find the time taken to reach 137 degrees
T(t) = Ts + Do e^-kt
137 = 60 + 125 e^-(0.0518t)
137 - 60 = 125 e^-(0.0518t)
77 = 125 e^-(0.0518t)
e^-(0.0518t)= 77/125
ln [e^-(0.0518t)] = ln(77/125)
-0.0518t = -0.4845
t = 0.4845/0.0518
t = 9.4 secs