Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.
Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
Answer:
let the number be y
4(y-7)=48
y-7=48/4
y-7=12
y=12+7=19
I would appreciate if my answer is chosen as a brainliest answer
Answer:
The inequality that comes from this equation is -2 < x < 0
Step-by-step explanation:
In order to solve this equation, we need to start by solving for the absolute value portion of the equation.
-5l2x + 2l + 7 > -3
-5l2x + 2l > -10
l2x + 2l < 2
Now we need to split the equation into two different portions. One with the absolute value symbol taken away. Then we do it again with the symbol flipped and the answer negated.
2x + 2 < 2
2x < 0
x < 0
And the negated version.
2x + 2 > -2
2x > -4
x > -2
