Let z be any number (like x would be)
if we set z equal to 2x-6y, then we get z = 2x-6y
The system
2x-6y = 8
2x-6 = 3
turns into this new system
z = 8
z = 3
but z is a single number. It can't be both 8 and 3 at the same time. So there are no solutions
Assume that the dimensions of the room in the plan are a (width ) by b (length),
such that a*b=30.
Since the scale is 1:100, a represents 100a, and b represents 100b.
So the actual dimensions are 100a by 100b.
The area is 100a*100b=a*b*10,000=30*10,000=300,000 (square units)
Answer: 300,000 (square units)
2+½, is just 2½, now divided by 1/4.
let's first convert the mixed fraction to improper, and then divide.
![\bf \stackrel{mixed}{2\frac{1}{2}}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{5}{2}\div \cfrac{1}{4}\implies \cfrac{5}{2}\cdot \cfrac{4}{1}\implies \cfrac{5}{1}\cdot \cfrac{4}{2}\implies 5\cdot 2\implies 10](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B5%7D%7B2%7D%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%5C%5C%5C%5C%0A%5Ccfrac%7B5%7D%7B2%7D%5Cdiv%20%5Ccfrac%7B1%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B2%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B1%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B1%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B2%7D%5Cimplies%205%5Ccdot%202%5Cimplies%2010)
12+8y you have to do like terms and the distributive property of 2(y+1)
Answer:
1. D -4
2. B -16
3. B. 37
4. E 13
5. C -646
6. E 12
Step-by-step explanation: