Say her hourly pay was $p for the day shift and $1.2p for the night shift.
(1) x = 55. Clearly insufficient: we need to know how these 55 hours are split between the day shift hours and the night shift hour.
(2) Grace's gross pay for the hours she worked on day shift last month was exactly 50% of her total gross pay for last month. Not sufficient.
(1)+(2) Say Grace worked h hours on the day shift and 55-h hours on the night shift. Thus, her pay for the the hours she worked on day shift is $ph and the total gross pay is $ph+(55-h)*1.2p. From (2) we have that ph=0.5(ph+(55-h)*1.2p) --> reduce by p: h=0.5(h+(55-h)*1.2). We have 1 variable, so we can solve for it. Sufficient.
Answer: C.
I hope this helps you
x^2-15x+36
x -3
x -12
(x-12)(x-3)
Answer:
<em>72</em>
Step-by-step explanation:
Since every year she watches it 3 times, she would watch 3·24 times when she is 24. 3·24=3·20+3·4=60+12=72
Answer: C) 0
The lines are parallel. They never cross. To have a solution, the lines need to intersect. Each intersection is a solution. That's why there are no solutions here. The system is inconsistent.
Note how the slopes are both 1/2 while the y intercepts are different. Parallel lines have equal slopes but different y intercepts.
Answer: she would have to use 5 seed packets
This is because every seed packet has 15 plants so 15 x 5 would equal 75
If you only use 4 packets you would be short 5 plants so you have to add another packet to get all 65 plants
