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lubasha [3.4K]
3 years ago
8

Solve for x. Enter your answer in the box below as a fraction in lowest terms, using the slash (/) as the fraction bar.

Mathematics
1 answer:
sashaice [31]3 years ago
7 0
X=1/30
Reduce 6/9 to 2/3, take 2/3 from both sides, then subtract the fractions
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What is the common differenice for this arithmetic sequence?
yaroslaw [1]

Answer:

The answer is D.

Step-by-step explanation:

The difference between each term is 4.

-2 - (-6) = 4

2 - (-2) = 4

6 - 2 = 4

10 - 6 = 4

8 0
3 years ago
Read 2 more answers
Graph f(x)= 1/x-2 include asymptotes, at least 5 points, and neatly sketch the branches
riadik2000 [5.3K]

Answer:

I attached the answer below.

Step-by-step explanation:

I recommend using Desmos, that's what I used. It helps graph and plot points.

Hope this helps!!

7 0
2 years ago
Find y when x = 12, if y = 2 when x = 5
AleksAgata [21]
Y = kx
k = y/x
k = 2/12
k = 1/6

so when x = 12
y = kx
y = 1/6(5)
y = 5/6

answer
when x = 5  y = 5/6
7 0
3 years ago
What is the following quotient?<br><br> Square root of 120/square root of 30
Mekhanik [1.2K]

Answer:

The square root of 120 is 10.9545.

The square root of 30 is 5.47723.

10.9545 divided by 5.47723 is approximately 2.0000073

7 0
3 years ago
A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus
aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis H_0:\mu= 1.6 (the null hypothesis always have the equal sign).

We have to test the null hypothesis

H_0:\mu= 1.6

The significance level for this test is 0.05

Calculation of the t-statistic:

t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

6 0
2 years ago
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