2 years ago

Rewrite the following parabola in vertex form by completing the square y= x^2 - 8x +13

Mathematics

1 answer:

Dmitry_Shevchenko [17]2 years ago

7 0

Answer:

y = (x - 4)² - 3

Step-by-step explanation:

<u>Given parabola:</u>

y = x² - 8x + 13

<u>Complete the square to convert the equation into vertex form:</u>

y = x² - 8x + 13 =
x² - 2*x*4 + 4² - 4² + 13 =
(x - 4)² - 16 + 13 =
(x - 4)² - 3

You might be interested in

How do you convert 16ft^2 to in^2

Jlenok [28]

16ft^2 * (12^2in^2)/(1ft^2)=2304in^2

4 0

3 years ago

Evaluate: (4x)2 when x = 3

ipn [44]

Answer:

if 4x square is the question the answer will be 144 or if 4x multiply by 2 then the answer will be 24

3 0

2 years ago

Read 2 more answers

Describe all the numbers that when rounded to the nearest thousand are 645,000. Please help due tomorrow giving 10 points

Dafna11 [192]

That rounds to 645, 000 -644,999

4 0

3 years ago

Read 2 more answers

? x2 +? +4 - (? a+?+4)

konstantin123 [22]

Ur mom is the answer

4 0

3 years ago

What is the best approximation of the length of segment QS? (Note: cos 80° = 0.17)

matrenka [14]

Answer: $QS=11.8cm$

Step-by-step explanation:

1. You have the following information:

- The lenght of $RS$ is 2 centimeters.

- The angle m∠S=80°.

- Cos80°=0.17

2. Therefore, you can calculate the lenght of the segment $QS$ as following:

$cos80=\frac{adjacent}{hypotenuse}$

$adjacent=2cm\\hypotenuse=QS\\cos80=0.17$

3. Substitute values and solve for $QS$ :

$0.17=\frac{2cm}{QS}\\QS=\frac{2cm}{0.17} \\QS=11.76cm$

4. To the nearest tenth:

$QS=11.8cm$

6 0

3 years ago