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3 years ago

What is the best approximation of the length of segment QS? (Note: cos 80° = 0.17)

Mathematics

1 answer:

matrenka [14]3 years ago

6 0

Answer: $QS=11.8cm$

Step-by-step explanation:

1. You have the following information:

- The lenght of $RS$ is 2 centimeters.

- The angle m∠S=80°.

- Cos80°=0.17

2. Therefore, you can calculate the lenght of the segment $QS$ as following:

$cos80=\frac{adjacent}{hypotenuse}$

$adjacent=2cm\\hypotenuse=QS\\cos80=0.17$

3. Substitute values and solve for $QS$ :

$0.17=\frac{2cm}{QS}\\QS=\frac{2cm}{0.17} \\QS=11.76cm$

4. To the nearest tenth:

$QS=11.8cm$

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3 years ago

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svet-max [94.6K]

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3 years ago

Read 2 more answers

1. Events A and B are dependent, P(A)=20%, P(BIA)=25%. What is P(A and B)?

Blizzard [7]

1. Given that events A and B are dependent, P(A)=20%, P(BIA)=25%. What is P(A and B)?
P(BIA)=[P(A and B)]/P(A)
it follows then that:
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2. Given that P(A) =12%, P(B)=48% and P(A or B)=50%. What is P(A and B)?
P(A or B)=P(A)+P(B)-P(A and B)
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3 years ago

Hernando and Rachel are factoring 2mp-6p+27-9m. Is either of them correct? Explain your reasoning,

vichka [17]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as Hernando and Rachel's solution are not provided. So, I will just solve the question directly.

Given

$2mp-6p+27-9m$