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Sindrei [870]
3 years ago
6

Question 1: Whose percentage increased more from 1984 to 2014, males or females? By how much more did it increase?

Mathematics
1 answer:
garik1379 [7]3 years ago
8 0

The percentage increase are applied to the number of male and female

from the previous period.

  • From 1984 to 2014, <u>the percentage of females increased more than males</u>.

Reasons:

Let <em>F</em> represent the initial number of females and let <em>M</em> represent the initial number of males before 1984.

We have;

In 1984

Number of females = F × 1.026 = 1.026·F

number of males = M × 1.031 = 1.031·M

In 1994

Number of females = 1.026·F × 1.032 = 1.058832·F

Number of males = 1.031·M × 1.032 = 1.063992·M

In 2004

Number of females = 1.058832·F × 1.056 = 1.118126592·F

Number of males = 1.063992·M × 1.049 = 1.116127608·M

In 2014

Number of females = 1.118126592·F × 1.066 = 1.191922947072·F

Number of males = 1.116127608·M × 1.059 = 1.181979136872·M

Therefore, between 1984 and 2014, we have;

The percentage increase of females = 1.191922947072 × 100 - 100 ≈  19.2%

The percentage increase of males = 1.181979136872 × 100 - 100 ≈ 18.2%

Therefore;

<u>The </u><u>percentage</u><u> </u><u>increase </u><u>of the </u><u>females </u><u>is </u><u>more than </u><u>the </u><u>males</u> by (1.191922947072 × 100 - 100) - (1.181979136872 × 100 - 100) ≈ 0.994%

Learn more about percentages and compounded percentages here:

brainly.com/question/3783619

brainly.com/question/1301322

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Step-by-step explanation:

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3 years ago
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Ksivusya [100]
<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

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<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

Perimeter\ of\ R=2(2x+3x)

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

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Hence, we get:

Perimeter\ of\ R=2(5x)

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Perimeter\ of\ R=10x

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

\text{Perimeter\ of\ square}=4s

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}

Now, we know that the area of a square is given by:

\text{Area\ of\ square}=s^2

and

\text{Area\ of\ Rectangle}=L\times B

Hence, we get:

\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}

and

\text{Area\ of\ Rectangle}=2x\times 3x

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\text{Area\ of\ Rectangle}=6x^2

Hence,

Ratio of the area of region R to the area of region S is:

=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}

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