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prisoha [69]
3 years ago
7

Mr. Blackwell’s company produces nuts and bolts. The total monthly profit for his company was $76,378. The profit earned from nu

ts was $3,428 more than the profit earned from bolts. Solve a system of equations that represents the situation.
profit from bolts: $ profit from nuts: $
Mathematics
1 answer:
Artist 52 [7]3 years ago
6 0

Answer:


Step-by-step explanation:

Oh my god I found cody

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Mathswatch Question! Mr Powers checks his electricity bill. Here are his meter readings. New reading: 6538 units, Old reading: 6
Setler79 [48]

Answer:

Cost = 284 x

Step-by-step explanation:

Given

Old = 6245\ units

New = 6538\ units

Required

The cost of units used

First, calculate the number of units used.

Units = New - Old

Units = 6538 - 6254

Units = 284

Next, multiply the units used by the cost per units,

Since the cost per unit is not given, we assume that it is x.

So, the total cost is:

Cost = Units * Cost\ per\ units

Cost = 284 * x

Cost = 284 x

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What is a monthly expense you should budget for when buying a car?
AfilCa [17]

Answer:

insurance payments every month

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Which state below is incorrect.
Reika [66]

Answer:

Last one

Step-by-step explanation:

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3 years ago
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A company manufactures televisions. The average weight of the televisions is 5 pounds with a standard deviation of 0.1 pound. As
Semenov [28]

Answer:

0.2564\text{ pounds}

Step-by-step explanation:

The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.

To find the X percentile for the television weights, use the formula:

X=\mu +k\sigma, where \mu is the average of the set, k is some constant relevant to the percentile you're finding, and \sigma is one standard deviation.

As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute \mu=5, k=1.282, and \sigma=0.1:

X=5+(1.282)(0.1)=5.1282

Therefore, the 90th percentile weight is 5.1282 pounds.

Repeat the process for calculating the 10th percentile weight:

X=5+(-1.282)(0.1)=4.8718

The difference between these two weights is 5.1282-4.8718=\boxed{0.2564\text{ pounds}}.

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3 years ago
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Neha is developing multiple neighborhoods. The following data points represent the number of new homes that will be built in eac
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Step-by-step explanation:

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