Answer: 0.457
multiply 3 by 7, and get 21
multiply 1 by 5, and get 5.
5 × 7 = 35.
fraction: 21/35 and 5/35
Subtract the numerators
21 − 5 = 16 = 16/35
Now we need to simplify the fraction that we have.
17 is larger than 16. So we're done reducing numbers.
<em>Our final answer: </em><em />
Hope this helps!
I am joyous to assist anytime.
<em>~Jarvis</em>
<em />
<em> </em>
Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.
Therefore, amount of the material left after 10 days would be 0.5 kg.
Therefore, amount of the material left after 20 days would be 0.25 kg.