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3 years ago

PLEASE HELP ASAP

Mathematics

1 answer:

Burka [1]3 years ago

6 0

Answer:

13 hours and 12 minutes

Step-by-step explanation:

you put 3.25 as a fraction which is 3 1/4. then I took 3 1/4 and misused it by 11 1/2. 23/2 - 13/4 = 8 1/4

then we took the 5/8 and divided it by 33/4 (3 1/4)

I got 13 1/5.

13 1/5 is 13 hours and 12 minutes.

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The model represents an equation. What value of X makes the equation true?

Anettt [7]

Answer:

D. 3

Step-by-step explanation:

Assuming the model represents an equation, the following can be deduced:

On the left side of the equation, the model shows we have 3 "x's", and 6 "1's". Let this represent:

3x + 6

On the right side of the equation, we have 2 "x's" and 9 "1's". Let this represent:

2x + 9.

The model would represent the equation below:

$3x + 6 = 2x + 9$

Solve for x

$3x + 6 - 2x = 2x + 9 - 2x$ (Subtracting 2x from both sides of the equation)

$x + 6 = 9$

$x + 6 - 6 = 9 - 6$ (subtracting 6 from both sides of the equation)

$x = 3$

8 0

3 years ago

Prove that the (n+1) term of a G.P of which the first term is a and third term is b,is equal to the (2n+1) term of a G.P of whic

Ahat [919]

Hello,

$u_{1} =a\\
 u_{3} =b\\

q= (\dfrac { u_{3} } {u_{1 } } )^ \frac{1}{2} \\\\\\

=(\dfrac{b}{a}) ^ \frac{1}{2} \\




 u_{n+1} =a*q^{n}=a* (\dfrac{b}{a}) ^ \dfrac{n}{2} \\


 \\\\\\\\\\\\v_{1} =a\\
 v_{5} =b\\

r= (\dfrac { v_{5} } {v_{1 } } )^ \frac{1}{4} \\\\\\


 v_{2n+1} =a*r^{2n}\\\\
=a* (\dfrac{b}{a}) ^ \dfrac{2n}{4}\\\\


=a* (\dfrac{b}{a}) ^ \dfrac{n}{2} \\





$

3 0

3 years ago

Jose traveled 315 miles in 7 hours. What was Jose's unit rate of speed, in miles per hour?

lidiya [134]

Answer:

45 miles in an hour

Step-by-step explanation:

315/7

8 0

3 years ago

A jogger runs 140 m due west, then changes direction for the second leg of her run. At the end of the run, she is 374 m away fro

USPshnik [31]

Answer:

The length of her second displacement = 247.12 m.

The direction of her second displacement = 31.24° from west.

Step-by-step explanation:

As per the question,

From the figure as drawn below,

Let the starting point be O. After running 140 m due west, she reached at point A.

∴ OA = 140 m

And At the end of the run, she is 374 m away from the starting point at an angle of 20° north of west.

∴ OP = 374 m

We have to find the distance AP = x.

By using the cosine rule in triangle OAP

$cos \theta = \frac{OA^{2}+OP^{2}-AP^{2}}{2\times OA\times OP}$

After putting the given value, we get

$cos 20= \frac{140^{2}+374^{2}-x^{2}}{2\times 140\times 374}$

$x^{2}=140^{2}+374^{2} - 2\times 140\times 374\times cos 20$

∴ x = 247.12 m

Hence,the length of her second displacement = 247.12 m.

Again,

By using the cosine rule in triangle OAP, we get

$cos \alpha = \frac{OA^{2}+AP^{2}-OP^{2}}{2\times OA\times AP}$

After putting the given value, we get

$cos \alpha = \frac{140^{2}+247.12^{2}-374^{2}}{2\times 140\times 247.12}$

∴ α = 148.759°

Hence, the direction of her second displacement = 180° - α = 180° - 148.759 = 31.24° from west.

8 0

4 years ago

What’s the mean,median, and mode of 11,14,16,15,32,23,27,27,23,43 ?

alexdok [17]

Step-by-step explanation:

mean- add all number/by the total nos

=231/10=23.1

median - the middle value of data after arranging in ascending order

11,14,15,16,23,23,27,27,32,43

therefore the median is 23

mode - is the no that has occurred more

so mode will be 23 and 27

8 0

4 years ago