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2 years ago

What is the answer and how do I get it

Mathematics

2 answers:

shepuryov [24]2 years ago

5 0

We know that 8 cubed is 8 x 8 x 8, which is 512

512 - 9 x 2 divide by 3

For the following, we will use PEMDAS

9 x 2 = 18

18 divide by 3 is 6

512 - 6 = 506

lora16 [44]2 years ago

4 0

Hope this helps you!!!

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What i the distance of A(0, 2), B(−3, 8)

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2 years ago

To rent a moving truck for the day, it costs $33 plus $1 for each mile driven. Write an expression for the total cost to rent th

alina1380 [7]

Answer:

Step-by-step explanation:

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3 years ago

Which of the following are identities? Check all that apply

Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

$\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}$

Double angle $tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}$

B) False,

No further development towards a Trig Identity

C) True

Double Angle Sine Formula $sin2\alpha =2sin\alpha *cos\alpha$

$sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)$

D) False No further development towards a Trig Identity

$[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)$

7 0

3 years ago

Read 2 more answers

F( y ) = y + y 2 - 3

ExtremeBDS [4]

F(y) = y + y^2 - 3

f(-2) = -2 + (-2^2) - 3
f(-2) = -2 + 4 - 3
f(-2) = -1

f(-4) = -4 + (-4^2) - 3
f(-4) = -4 + 16 - 3
f(-4) = 9

f(0) = 0 + 0^2 - 3
f(0) = -3

f(2) = 2 + 2^2 - 3
f(2) = 2 + 4 - 3
f(2) = 3

f(4) = 4 + 4^2 - 3
f(4) = 4 + 16 - 3
f(4) = 17

7 0

3 years ago

A)<br> Identify all x-values not in the domain of<br> y=(x² – 4x²) / (3x² - 6x – 24)

True [87]

Answer:

x ≠ 4 or -2

Step-by-step explanation:

the denominator cannot be zero, so factor the bottom equation to get the zeros and those are the domain restrictions.

3x^2 - 6x - 24 ≠ 0

3(x^2 - 2x - 8) ≠ 0 (factor out a 3)

3(x - 4)(x + 2) ≠ 0 (factor equation)

x ≠ 4, x ≠ -2 (use zero product property to find zeros)

3 0

3 years ago