Find x . Please help I’m begging
1 answer:
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Answer:
see below
Step-by-step explanation:
f(x) = 4x^2 + 8x − 5
To find the x intercepts set y = 0
0 =4x^2 + 8x − 5
Factor
0=(2x-1)(2x+5)
Using the zero product property
2x-1 =0 2x+5 =0
2x=1 2x = -5
x = 1/2 x = -5/2
The x intercepts are ( 1/2 ,0) and ( -5/2,0)
Rewriting in vertex form by completing the square
4 ( x^2 + 2x) -5
4 ( x^2+2x +1) -4*1 -5
4 ( x+1) ^2 -9
Vertex form is
a( x-h) ^2 +k where ( h,k) is the vertex
The vertex is ( -1,-9)
We know it opens upwards since a > 0
Plot the vertex and the x intercepts
The graph is symmetric on based on the vertex
Answer:
Step-by-step explanation:
We want an exponential function that goes through the two points (0, 8) and (2, 200).
Since a point is (0, 8), this means that y = 8 when x = 0. Therefore:
Simplify:
So we now have:
Likewise, the point (2, 200) tells us that y = 200 when x = 2. Therefore:
Solve for b. Dividing both sides by 8 yields:
Thus:
Hence, our exponential function is: