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n200080 [17]
3 years ago
11

Log and antilog of 5. 037​

Mathematics
1 answer:
N76 [4]3 years ago
3 0
Use AIRMATH for faster repos
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Evaluate the expression |- 178|
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A 16 foot ladder rests against the side of a house and the base of the ladder is 4 feet away. How high above the ground is the t
PtichkaEL [24]

Answer:

  15.5 ft

Step-by-step explanation:

The geometry of the problem can be modeled by a right triangle with hypotenuse 16 ft and one side length of 4 ft. If x represents the height of the ladder on the building, then the Pythagorean theorem tells us ...

  x^2 + (4 ft)^2 = (16 ft)^2

  x^2 = 240 ft^2 . . . . . . subtract 16 ft^2

  x ≈ 15.5 ft . . . . . . . . . . take the square root

The top of the ladder is about 15.5 ft above the ground.

8 0
3 years ago
Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
Irina18 [472]

Answer:

x = 97.6

Step-by-step explanation:

cos = adjacent over hypotenuse

cos(55)=\frac{56}{x}

* multiply each side by x *

cos(55)*x=xcos(55)\\\frac{56}{x} *x=56\\56=xcos(55)

* divide each side by cos ( 55 ) *

\frac{xcos(55)}{cos(55)} =x\\\frac{56}{cos(55)} =97.63302055

we're left with x = 97.63302055

Our last step is to round to the nearest tenth of a foot

We get that x = 97.6

4 0
3 years ago
What is the answer to 0.5(2x + 8) = x - 4
svp [43]

0.5(2x+8) = x-4\\\\\implies \dfrac 12 (2x+8 ) = x-4\\\\\implies  2x+8 =  2x-8\\\\\implies 8=-8\\\\\text{Which is not true, so there are no solution.}

5 0
2 years ago
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