33.3%
Since we are given that it is an even number, we know there is only 3 options (2, 4, 6). Since only one of them is an even number, we know that we need the fraction 1/3 or 33.3% for a probability.
Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
6.66, with a bar on top of the last two sixes
Answer:
2x = 10
Step-by-step explanation:
7 + 3x = 22
-7 -7
Subtract 7 from both sides (you are trying to get the variable alone, and to do that, you have to get every other number to 0. <em>7 - 7 = 0</em>. BUT, whatever you do, you have to do to both sides.)
3x = 15
/3 /3
Divide both sides by three to get the variable alone.
x = 5
Now, plug in the value of x to the second equation and solve.
2(5) = ? --> 10
Answer:
whatcha asking here buddy?
Step-by-step explanation:
