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const2013 [10]
3 years ago
7

What is the standard form of (2-4i)(3+5i)/(3+i)?

Mathematics
2 answers:
Eva8 [605]3 years ago
8 0

Answer:

AKA Letter Choice E on Plato!!

german3 years ago
5 0
\dfrac{(2-4i)(3+5i)}{3+i}=\\
\dfrac{6+10i-12i+20}{3+i}=\\
\dfrac{26-2i}{3+i}=\\
\dfrac{(26-2i)(3-i)}{9+1}=\\
\dfrac{78-26i-6i-2}{10}=\\
\dfrac{76-32i}{10}=\\
\dfrac{38}{5}-\dfrac{16}{5}i
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-1(3a-2)

Step-by-step explanation:

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Evaluate x(-2) - 16<br> When x = 2
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\huge\text{Hey there!}

\huge\boxed{\rm{x(-2) - 16}}

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Write an equation for the perpendicular bisector of the line segment joining the two points.
Leona [35]
Points (1, 7)  and  (-3, 2)

Slope for a line between (x₁, y₁) and (x₂, y₂) , m = (y₂ -y₁) / (x₂- x₁)

The slope for the line joining the two points =  (2 - 7) / (-3 - 1) = -5/-4

Slope = 5/4

Hence the perpendicular bisector would have a slope of -1/(5/4) = -4/5

By condition of perpendicularity

For points (1, 7)  and  (-3, 2),

Formula for midpoints for (x₁, y₁) and (x₂, y₂) is ((x₁ +x₂)/2 , (y₁+ y₂)/2)

Midpoint for (1, 7)  and  (-3, 2) = ((1+ -3)/2 , (7+2)/2) = (-2/2, 9/2)

= (-1, 9/2)

Since the slope of perpendicular bisector is -4/5 and passes through the midpoint (-1, 9/2)

Equation  y - y₁ = m (x - x₁)

                y - 9/2 = (-4/5) (x - -1)
           
                y - 9/2 = (-4/5)(x + 1)

               5(y - 9/2) = -4(x + 1)

               5y - 45/2 = -4x - 4

                 5y =  -4x - 4 + 45/2
           
                5y + 4x = 45/2 - 4

                  5y + 4x = 22  1/2  - 4 =  18 1/2

                  5y + 4x =  37/2

                  10y + 8x = 37

The equation of the line to perpendicular bisector is 10y + 8x = 37
7 0
4 years ago
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