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nalin [4]
4 years ago
6

The area of the base of a rectangular prism is 32 1/ 2 cm2. The height of the prism is 8 cm. What is the volume of the prism? A)

72 1 2 cm3 B) 95 cm3 C) 150 cm3 D) 260 cm3
What is the area of the green triangle?
A) 23 cm2
B) 30 cm2
C) 46 cm2
D) 65 cm2

What is the volume of the triangular prism?
A) 8 ft3
B) 12 ft3
C) 16 ft3
D) 24 ft3

What is the surface area of the triangular prism?
A) 991 cm2
B) 1024 cm2
C) 1400 cm2
D) 1984 cm2
Mathematics
1 answer:
Fiesta28 [93]4 years ago
7 0
<h2><em><u>Math Question Answered. </u></em></h2><h2><em><u>100% Correct. C;</u></em></h2>

Answer:

1. What is the area of the green triangle?

A) 23 cm2  

B) 30 cm2  

C) 46 cm2  

D) 65 cm2

Correct answer is : D) 260 cm3

Step-by-step explanation:

260cm3  

V = (area of base)(height)

(32  1/

2  cm2) (8cm)

260 cm3

2. Answer:

What is the volume of the triangular prism?

A) 8 ft3  

B) 12 ft3  

C) 16 ft3  

D) 24 ft3

   Correct Answer is: A) <u>8 ft^3</u>

Step-by-step explanation:

Volume =  1

/2  × base × height × length

Volume =  1

/2 × 4 × 4 × 1 = 8

3. Answer:

What is the surface area of the triangular prism?

A) 991 cm2  

B) 1024 cm2  

C) 1400 cm2  

D) 1984 cm2

    Correct answer:  D) <u>1984 cm2</u>

Step-by-step explanation:

SA = bh + (s1 + s2 + s3)H

SA = 24(16) + (24 + 20 + 20)25

SA = 384 + (64)(25)

SA = 384 + 1600

SA = 1984 cm2

Answer:

What is the area of the green triangle?

A) 23 cm2  

B) 30 cm2  

C) 46 cm2  

D) 65 cm2

       Correct Answer: D) 65 cm2

<h2>HOPE THIS HELPED YOU A-LOT </h2>
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Use this information to answer the questions. University personnel are concerned about the sleeping habits of students and the n
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Answer:

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

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If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of  students reported experiencing excessive daytime sleepiness (EDS) is significantly higher than 0.5 or the half.

Step-by-step explanation:

1) Data given and notation

n=377 represent the random sample taken

X=209 represent the students reported experiencing excessive daytime sleepiness (EDS)

\hat p=\frac{209}{377}=0.554 estimated proportion of students reported experiencing excessive daytime sleepiness (EDS)

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

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z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.5:  

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Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.097)=0.018  

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