Question

Given △MON≅△PQR with MO=20 , MN=32 and PR=3x−10. Find the value of x. show your work

Answer 1

Answer:

$x=14$

Step-by-step explanation:

we know that

If two figures are congruent, then its corresponding sides and its corresponding angles are congruent

In this problem

△MON≅△PQR

so

corresponding sides

MO≅PQ

MN≅PR

ON≅QR

corresponding angles

∠M≅∠P

∠O≅∠Q

∠N≅∠R

therefore

MN=PR

substitute the given values

$32=3x-10$

solve for x

$3x=32+10$

$3x=42$

$x=14$