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iVinArrow [24]
3 years ago
7

Given △MON≅△PQR with MO=20 , MN=32 and PR=3x−10. Find the value of x. show your work

Mathematics
1 answer:
aliya0001 [1]3 years ago
3 0

Answer:

x=14

Step-by-step explanation:

we know that

If two figures are congruent, then its corresponding sides and its corresponding angles are congruent

In this problem

△MON≅△PQR

so

corresponding sides

MO≅PQ

MN≅PR

ON≅QR

corresponding angles

∠M≅∠P

∠O≅∠Q

∠N≅∠R

therefore

MN=PR

substitute the given values

32=3x-10

solve for x

3x=32+10

3x=42

x=14

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Answer:

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Step-by-step explanation:

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Area = 11*4\\\\      =44 feet^2

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Area= \frac{1}{2} *Base*Height

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The difference of six times a number and 7 is -49
gtnhenbr [62]
Greetings!

"<span>The difference of six times a number and 7 is -49"...

In number and variables, this would be:
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<span>
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Step-by-step explanation:


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Answer:

1.U={1,2,3,4,5}

A={2}

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2.U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

Step-by-step explanation:

We are given that A\cap (B\cup C) and A\cup (B\cap C)

are different sets

1.We have to construct a universe set U and non empty sets A,B and C so that above set in fact the same

Suppose U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

B\cap C=\phi

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A\cap (B\cup C)={2}\cap{2,3,4,5}={2}

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2.We have to construct a universe set U and non empty sets A,B and C so that  above sets are in fact different

Suppose U={1,2,3,4}

A={1,2}

B={2,3}

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B\cap C=\phi

B\cup C={2,3,4}

A\cup (B\cap C)={1,2}\cup \phi={1,2}

A\cap (B\cup C)={1,2}\cap {2,3,4}={2}

Hence, A\cap (B\cup C)\neq A\cup (B\cap C)

3 0
3 years ago
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