PLEASE HELP WHAT IS THE DOMAIN AND RANGE OF THIS GRAPH

A) Identify all x-values not in the domain of y=(x² – 4x²) / (3x² - 6x – 24)

True [87]

Answer:

x ≠ 4 or -2

Step-by-step explanation:

the denominator cannot be zero, so factor the bottom equation to get the zeros and those are the domain restrictions.

3x^2 - 6x - 24 ≠ 0

3(x^2 - 2x - 8) ≠ 0 (factor out a 3)

3(x - 4)(x + 2) ≠ 0 (factor equation)

x ≠ 4, x ≠ -2 (use zero product property to find zeros)

3 0

3 years ago

Please please help |q-8|=14

Maslowich

Answer:

22, -6

Step-by-step explanation:

q-8=14 or 8-q=14

q=22 or q= -6

4 0

3 years ago

Read 2 more answers

What is the solution of each equation? 3. 7 + n = –5 A. –12 B. –2 C. 2 D. 12

Anna71 [15]

You need to download the app Photo math

8 0

3 years ago

We wish to estimate what percent of adult residents in a certain county are parents. Out of 300 adult residents sampled, 144 had

ser-zykov [4K]

Answer:

90% confidence interval for the proportion p of adult residents who are parents in this county is [0.433 , 0.527].

Step-by-step explanation:

We are given that we wish to estimate what percent of adult residents in a certain county are parents. Out of 300 adult residents sampled, 144 had kids.

Firstly, the pivotal quantity for 90% confidence interval for the proportion p of adult residents who are parents in this county is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of adults residents who are parents in this county in a sample of 300 adults = $\frac{144}{300}$ = 48%

n = sample of adults residents = 300

p = population proportion of adults

Here for constructing 90% confidence interval we have used One-sample z proportion statistics.

So, 90% confidence interval for the population proportion, p is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90 {As the critical value of z at 5%

significance level are -1.6449 & 1.6449}

P(-1.6449 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.6449) = 0.90

P( $-1.6449 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.6449 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.90

P( $\hat p-1.6449 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.6449 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.90

90% confidence interval for p = [ $\hat p-1.6449 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.6449 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.48-1.6449 \times {\sqrt{\frac{0.48(1-0.48)}{300} } }$ , $0.48+1.6449 \times {\sqrt{\frac{0.48(1-0.48)}{300} } }$ ]

= [0.433 , 0.527]

Therefore, 90% confidence interval for the proportion p of adult residents who are parents in this county is [0.433 , 0.527].

4 0

3 years ago

Select all the expressions that give the area of the figure in square units.

vodomira [7]

Where? Are the expressions?

8 0

3 years ago