PLEASE HELP WHAT IS THE DOMAIN AND RANGE OF THIS GRAPH

4x − 8y = –20<br> 4x − 7y = –15

Alja [10]

Y = 5
x = 5
good luckkkkkkk

8 0

3 years ago

Help answer this plz

Sphinxa [80]

X=-1 is the answer. Hope that helps!

8 0

4 years ago

Read 2 more answers

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is:

$T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20$

From the first equation:

$d_1 = 40t_1$

$t_1 = \frac{d_1}{40}$

Replacing in the second equation:

$60 = \frac{d_1 - 20}{t_1 - 2}$

$d_1 - 20 = 60t_1 - 120$

$d_1 - 20 = 60\frac{d_1}{40} - 120$

$d_1 = \frac{3d_1}{2} - 100$

$d_1 - \frac{3d_1}{2} = -100$

$-\frac{d_1}{2} = -100$

$\frac{d_1}{2} = 100$

$d_1 = 200$

Thus, the total distance is:

$T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380$

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0

3 years ago

Need help.....................................

adoni [48]

Answer: w, 0

Step-by-step explanation:

you can see that G has the same distance from 0 as E does, so you can just take away the - sign. It hasn't left the line so its still 0.

8 0

3 years ago

Isabel wrote this mystery problem. The quotient is multiple of 6. The dividend is multiple of 9. The divisor is a factor of 12.

Marina86 [1]

Answer:

Consider the expression $q=\frac{a}{b}$ . q is called the quotient, a is is the dividend and b is the divisor.

Since q is a multiple of 6, then q has the form $q=6k$ for some integer k.

Since a is a multiple of 9, then a has the form $a=9s$ for some integer s.

Since b is a factor of 12, then if 12 can be expressed of the form $12=c*b$ , for c an integer. Then b has the form $b=\frac{12}{m}$

Replacing the preview expression in the initial expression we obtain:

$6k=\frac{9s}{\frac{12}{m}}=\frac{9sm}{12}\\6*12k=9sm\\72k=9sm\\72k-9sm=0$

Then $72k-9sm=0,\; for \; k,s,m\in \mathbb{Z}$ is a equation to Isabel's problem.

3 0

3 years ago