Question

declaration a plane at the uniform rate of 8.0 meter/second ^2 , a pilot stops the plane in 484 meters. how fast was the plane going before breaking began ?

Answer 1

Answer:

  88 m/s

Step-by-step explanation:

The appropriate formula relating initial speed v, acceleration a, and distance d is ...

  v² = 2ad

  v² = 2(8 m/s²)(484 m) = 7744 m²/s²

Taking the square root gives ...

  v = √7744 m/s = 88 m/s