3. 12 a
4. 7b-10
all you have to do is add up all of the sides.
The way we simplify this is by using the distributive property and multiply every term by 0.5. When we do this we get 2a+3b
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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Theoretical probability (TP) is given by:
TP=[Number of favorable (desired) outcomes]/[Total number of possible outcomes]
From the information given:
Number of purple blocks=19
Total number of possible outcomes=125
thus;
TP=19/125
=0.152
There is 36 ways the dice come up, 6 for each dice. thats 8/36 or 2/9. :)
