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2 years ago

13

A car travels 10 km southeast and then 15 km in a direction 60° north of east. Find the magnitude of the car's resultant vector.

1 answer:

Aliun [14]2 years ago

7 0

Answer:

-10sin45+15cos60=Hor distance = 5.92 km

-10cos45+15sin60=ver distance = .429 km

resultant is sqrt(5.922+.4292)= 5.94 km at angle arctan(.429/5.92)= 1.77 degrees north of east

Step-by-step explanation:

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PSYCHO15rus [73]

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Step-by-step explanation:

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3 years ago

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pogonyaev

Given:
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3 years ago

Read 2 more answers

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Tomtit [17]

Answer:

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Step-by-step explanation:

Given:

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3 years ago

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nadya68 [22]

Answer:

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Step-by-step explanation:

2 is repeated twice in the function.

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3 years ago

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2 years ago