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artcher [175]
3 years ago
13

A car travels 10 km southeast and then 15 km in a direction 60° north of east. Find the magnitude of the car's resultant vector.

​
Mathematics
1 answer:
Aliun [14]3 years ago
7 0

Answer:

-10sin45+15cos60=Hor distance = 5.92 km

-10cos45+15sin60=ver distance = .429 km

resultant is sqrt(5.922+.4292)= 5.94 km at angle arctan(.429/5.92)= 1.77 degrees north of east

Step-by-step explanation:

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I need help with this problem
Dmitriy789 [7]

Answer:

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Step-by-step explanation:

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3 years ago
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2x + 4y = 1<br> 3x - 5y = 7<br> solve the simultaneous equations x
Norma-Jean [14]

Answer:

(x,y)=(3/2, -1/2)

Step-by-step explanation:

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...........................

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