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Nuetrik [128]
2 years ago
13

Can someone help me on this?

Mathematics
1 answer:
Mnenie [13.5K]2 years ago
5 0

Answer:

Step-by-step explanation:

We know that cosx = sin(\pi - x)

We can apply it here:

sin(55°) = cosx

cos(\pi - 55°) = cosx

Now we apply the arccos to both sides:

x = \pi - 55° + 2k\pi or x = -\pi - 55° + 2k\pi

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Which expression is equivalent to
givi [52]

Answer:

\boxed{D. 9x + 36}

Step-by-step explanation:

<em>Hey there!</em>

<u><em>Given info</em></u>

9(x + 4)

<u><em>Solve!</em></u>

9*x = <u>9x</u>

9*4 = <u>36</u>

<u><em>Answer</em></u>

<u>9x + 36</u>

D. 9x + 36

<em>Hope this helps :)</em>

6 0
4 years ago
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The following M &amp; M colors are in the bowl: 4 yellow, 6 orange, 3 green, 5 blue, 2 brown. What is the probability of selecti
vladimir1956 [14]

Answer:

There are non, coz I ate all the blue ones

8 0
3 years ago
Find the GCF and LCM of 217x328x11 and 213x345x74and explain your reasoning.
AfilCa [17]

Answer:

Given expressions are,

217 x 328 x 11

213 x 345 x 74,

Since, 217 = 7 × 31

328 = 2 × 2 × 2 × 41,

11 = 1 × 11,

So, we can write, 217 x 328 x 11 = 7 × 31 × 2 × 2 × 2 × 41 ×  1 × 11

Now, 213 = 3 × 71

345 = 3 × 5 × 23,

74 = 2 × 37,

So, 213 x 345 x 74 = 3 × 71 × 3 × 5 × 23 × 3 × 5 × 23

Thus, GCF ( greatest common factor ) of the given expressions = 1 ( because there are no common factors )

We know that if two numbers have GCF 1 then their LCM is obtained by multiplying them,

Hence, LCM ( least common multiple ) of the given expressions = 217 x 328 x 11 x 213 x 345 x 74

6 0
4 years ago
-x + 2y = 3<br> 2x – 3y = -6
s2008m [1.1K]

Answer:

x = -3

y = 0

Step-by-step explanation:

<u>Given</u><u> </u><u>equations</u><u> </u><u>:</u><u>-</u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u><u> </u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u>

<u>-x</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>-</u><u> </u><u>2</u><u>y</u><u> </u>

<u>x</u><u> </u><u>=</u><u> </u><u>2</u><u>y</u><u> </u><u>-</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u><u> </u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u>

<u>2</u><u>x</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>+</u><u> </u><u>3</u><u>y</u><u> </u>

<u>x =  \frac{ - 6 + 3y}{2}</u>

<u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>Equating</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>x</u><u> </u><u>=</u><u> </u><u>x</u><u> </u>

<u>2y - 3 =  \frac{ - 6 + 3y}{2}</u>

4y - 6 = -6 + 3y

4y - 3y = -6 + 6

y = 0

Putting value of y in ( iii )

x = 2y - 3

x = 2 ( 0 ) - 3

x = -3

4 0
3 years ago
A circular running track 1/3 is mile long. Elena runs on this track, completing each lap in 1/15 of an hour. Elena's running spe
jek_recluse [69]

Answer:

2.22m/s

Step-by-step explanation:

Distance = Velocity/Time

533.33m = V/4minutes

V = 533.33/240 seconds

V = 2.22m/s

3 0
3 years ago
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