Question

Can someone help me on this?

Answer 1

Answer:

Step-by-step explanation:

We know that cosx = sin($\pi$ - x)

We can apply it here:

sin(55°) = cosx

cos($\pi$ - 55°) = cosx

Now we apply the arccos to both sides:

x = $\pi$ - 55° + 2k$\pi$ or x = -$\pi$ - 55° + 2k$\pi$