A baseball player running forward at 3 meters per second throws a ball with a velocity of 20 meters per second at an angle of 20
o with the horizontal. What is the resultant speed and direction of the throw?
2 answers:
Answer:
22.84 meters per second
17.43° with the horizontal
Step-by-step explanation:
steps on precalculus textbook p. 496
Answer:
22.8 m/s at 17.4°
Step-by-step explanation:
Horizontal component:
vₓ = 3 + 20 cos 20° = 21.8
Vertical component:
vᵧ = 0 + 20 sin 20° = 6.84
Magnitude:
v² = vₓ² + vᵧ²
v² = (21.8)² + (6.84)²
v = 22.8 m/s
Direction:
θ = atan(vᵧ / vₓ)
θ = atan(6.84 / 21.8)
θ = 17.4°
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