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3 years ago

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Marc saved 30% of his monthly salary each month. His monthly salary in December was $ 3650. In January, his salary increased by

12%. How much more did he save in January than in December?plz help me.

2 answers:

DiKsa [7]3 years ago

8 0

Marc saved $2,533 in January than in December.

Step by Step calculation.

Given the details below :

Salary In December =$3,650

In January, Increased by 12%

Marc saves 30% of $3,650 in December

New salary can then be calculated as :

= Initial salary * % increase / 100 + Initial salary

= 3,650 * 12 / 100 + 3,650

= 3,650 * 0.12 + 3,650

= 4,088

The difference will now be

= 4,088 - 3650

= $438

Since Marc saves in December 30% of $3,650

= 30% of $3,650

= $1,095

Saves in January

= 1,095 + 438

= $2,533

Learn more here : https://brainly.in/question/36065141

Musya8 [376]3 years ago

3 0

$\tt \huge{ \underline{ \overline{ \fbox{ \pink{Answer}}}}} \\ \tt \: → 438 \: \: saves \: \: much \: \: more \: \: and \: \: total \\ \: \tt is \: \: 2,533 \\ \tt \bf Step-by-step \: \: Explaination : \\ \\ \tt \bf Given :$

Salary In December =$3,650

In January, Increased by 12%

Marc saves 30% of $3,650 in December

$\tt \bf \: To \: \: Find :\tt How \: \: much \: \: more \: \: will \: \: marc \: \: save \\ \tt \: \: in \: \: January \\ \\ \: \large\mathcal{ \underline{ \green{Solution}}} \\$

$\tt \: New \: \: Salary \: = initial \: salary\times \frac{ \% \: increase }{100} + initial \: salary \\ \\ \: \: = \: 3650 \times \frac{12}{100} + 3650 \\ \\ \: \: \: \tt →4,088 \\ \\ \\$

Difference = 4,088 - 3650 = $438

Marc saves in December 30% of $3,650 = $1,095

Saves in January = 1,095 + 438 →$ 2,533

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Answer:

(8, 20)

Step-by-step explanation:

Let's input each values of the ordered pair given as options to see which one satisfy the equation y = 16 + 0.5x

==>Option 1: (0, 18)

18 = 16 + 0.5(0)

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Option 1 is incorrect.

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19.5 = 16 + 0.5(5)

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Incorrect.

==>Option 3: (8, 20)

20 = 16 + 0.5(8)

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==>Option 4: (10, 21.5)

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3 years ago

Sonny has $24 and Jerry has $9.56. What is the total amount of money, in

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Answer:

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3 years ago

Find the mass and the center of mass of a wire loop in the shape of a helix (measured in cm: x = t, y = 4 cos(t), z = 4 sin(t) f

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Answer:

<u>Mass</u>

$\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)$

<u>Center of mass</u>

<em>Coordinate x</em>

$\displaystyle\frac{(\displaystyle\frac{(2\pi)^4}{4}+32\pi)}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

<em>Coordinate y</em>

$\displaystyle\frac{16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

<em>Coordinate z</em>

$\displaystyle\frac{-16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

Step-by-step explanation:

Let W be the wire. We can consider W=(x(t),y(t),z(t)) as a path given by the parametric functions

x(t) = t

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for 0 ≤ t ≤ 2π

If D(x,y,z) is the density of W at a given point (x,y,z), the mass m would be the curve integral along the path W

$m=\displaystyle\int_{W}D(x,y,z)=\displaystyle\int_{0}^{2\pi}D(x(t),y(t),z(t))||W'(t)||dt$

The density D(x,y,z) is given by

$D(x,y,z)=x^2+y^2+z^2=t^2+16cos^2(t)+16sin^2(t)=t^2+16$

on the other hand

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and we have

$m=\displaystyle\int_{W}D(x,y,z)=\displaystyle\int_{0}^{2\pi}D(x(t),y(t),z(t))||W'(t)||dt=\\\\\sqrt{17}\displaystyle\int_{0}^{2\pi}(t^2+16)dt=\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)$

The center of mass is the point $(\bar x,\bar y,\bar z)$

where

$\bar x=\displaystyle\frac{1}{m}\displaystyle\int_{W}xD(x,y,z)\\\\\bar y=\displaystyle\frac{1}{m}\displaystyle\int_{W}yD(x,y,z)\\\\\bar z=\displaystyle\frac{1}{m}\displaystyle\int_{W}zD(x,y,z)$

We have

$\displaystyle\int_{W}xD(x,y,z)=\sqrt{17}\displaystyle\int_{0}^{2\pi}t(t^2+16)dt=\\\\=\sqrt{17}(\displaystyle\frac{(2\pi)^4}{4}+32\pi)$

so

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sashaice [31]

I'll use subscript notation for brevity, i.e.

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