Determine by checking the group axiom (Associativity) whether this set is a group:
1 answer:
Let x, y, z ∈ C, the set of complex numbers.
By definition of ○,
(x ○ y) ○ z = (x + y - 2i) ○ z
… = (x + y - 2i) + z - 2i
… = x + y + z - 4i
and
x ○ (y ○ z) = x ○ (y + z - 2i)
… = x + (y + z - 2i) - 2i
… = x + y + z - 4i
so (x ○ y) ○ z = x ○ (y ○ z), which means ○ is indeed associative under C.
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Answer:
13/63
Step-by-step explanation:
7/9-4/7=49/63-36/63=13/63
ok
under the -4 is a 16
under the 0 is a 4
under the 8 is a -20
Your Welcome
1 is 16 units and 2 is idk
since AM/AC = AN/AB = 2/5,
then ∆ABC similar to ∆ANM.
since ∆ABC ~ ∆ANM,
then MN || BC.
by similarity
MN = BC•2/5 = 8
M/3.2*3.2=15*3.2
M=48
I think