I wonder if you mean to write ![\sqrt[3]{256}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B256%7D)
in place of 
...
If you meant what you wrote, then we have
If you meant to write (the cube root of 256), then we could go on to have
![\sqrt[3]{256}=\sqrt[3]{16^2}=\sqrt[3]{(4^2)^2}=\sqrt[3]{4^4}=\sqrt[3]{4^3\cdot4}=4\sqrt[3]4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B256%7D%3D%5Csqrt%5B3%5D%7B16%5E2%7D%3D%5Csqrt%5B3%5D%7B%284%5E2%29%5E2%7D%3D%5Csqrt%5B3%5D%7B4%5E4%7D%3D%5Csqrt%5B3%5D%7B4%5E3%5Ccdot4%7D%3D4%5Csqrt%5B3%5D4)
Answer:
p = 3/4 or 0.75
Step-by-step explanation:
your equation: 60p = 45
divide both sides by 60: p = 45/60
simply the fraction by dividing the numerator and denominator by 15: p = 3/4
your answer: 3/4 or 0.75
Answer:
(8, 2 )
Step-by-step explanation:
Given the 2 equations
x + 4y = 16 → (1)
- x + 3y = - 2 → (2)
Adding the 2 equations term by term will eliminate the x- term
0 + 7y = 14
7y = 14 ( divide both sides by 7 )
y = 2
Substitute y = 2 into either of the 2 equations and solve for x
Substituting into (1)
x + 4(2) = 16
x + 8 = 16 ( subtract 8 from both sides )
x = 8
solution is (8, 2 )
<span>4(6) + 7 (5 - 3 )
= 24 + 7(2)
= 24 + 14
= 38
answer
</span><span>D: 38</span>
