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Zepler [3.9K]
3 years ago
12

PLEASE HELP ME!! I REALLY NEED HELP GRAPHING IT!!Autumn runs a farm stand that sells peaches and grapes. Each pound of

Mathematics
1 answer:
Dafna1 [17]3 years ago
4 0
10lbs of peaches. 45 pounds of grapes.

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Please help with this question!
Nutka1998 [239]

Answer:

a=sqrt[50]; ?=50

Step-by-step explanation:

Using the Pytagorean theorem in the right triangle:

A^2+B^2=C^2, with A=a, B=a, and C=10

Replacing in the formula:

a^2+a^2=10^2

Adding like terms:

2a^2=100

Solving for a: Dividing both sides of the equation by 2:

2a^2/2=100/2

a^2=50

Square root both sides of the equation:

sqrt(a^2)=sqrt(50)

a=sqrt(50)

8 0
3 years ago
Mark estimated that the drive would take 3,000 minutes. It ended up taking 2 days. Did the drive take longer or shorter than he
Arlecino [84]

Answer:

The driver took shorter than estimated

It took shorter by 2 hours( 120

minutes)

Step-by-step explanation:

Firstly we want to know if the drive took longer or shorter

By 2 days, the number of hours will be 2 * 24 = 48 hours ( recall 24 hours = 1 day

now , since 60 minutes give one hour, then 48 hours will me 60 * 48 = 2,880 hours

This is less than 3,000 hours

By how much?

Simply subtract the value of minutes in 48 hours from 3,000 = 3000-2880 = 120 minutes ( or two hours)

5 0
3 years ago
a piece of string, 48 cm long, is folded in half lenghtways, then in half again and then in half again
ss7ja [257]
It should be 3cm if I did it right
6 0
3 years ago
Find the measure of the angle, round to the nearest tenth: Sin X = .7547
dimulka [17.4K]
SIN(x) = .7547
X = INVERSE-SIN(.7547)
X = 49.0 degrees
4 0
3 years ago
Lim x--> 0 (e^x(sinx)(tax))/x^2
Tom [10]

Make use of the known limit,

\displaystyle\lim_{x\to0}\frac{\sin x}x=1

We have

\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)

since \tan x=\dfrac{\sin x}{\cos x}, and the limit of a product is the same as the product of limits.

\dfrac{e^x}{\cos x} is continuous at x=0, and \dfrac{e^0}{\cos 0}=1. The remaining limit is also 1, since

\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1

so the overall limit is 1.

4 0
3 years ago
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