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2 years ago

Three teachers have purchased candy for a school carnival. each bag of candy weigh is 1 1/4 pounds

Mathematics

1 answer:

polet [3.4K]2 years ago

5 0

Answer:

3 * 1.25 = 3.75

Step-by-step explanation:

3.75 also equals 3 3/4

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I don’t understand this I need help please

scoray [572]

The answer is B 2+(-35)

8 0

3 years ago

Read 2 more answers

Verify a(b-c)=ab-ac for a=1.6;b=1/-2;& c=-5/-7

harina [27]

Given:

$a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}$

To verify:

$a(b-c)=ab-ac$ for the given values.

Solution:

We have,

$a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}$

We need to verify $a(b-c)=ab-ac$ .

Taking left hand side, we get

$a(b-c)=1.6\left(\dfrac{1}{-2}-\dfrac{-5}{-7}\right)$

$a(b-c)=1.6\left(-\dfrac{1}{2}-\dfrac{5}{7}\right)$

Taking LCM, we get

$a(b-c)=1.6\left(\dfrac{-7-10}{14}\right)$

$a(b-c)=\dfrac{16}{10}\left(\dfrac{-17}{14}\right)$

$a(b-c)=\dfrac{8}{5}\left(\dfrac{-17}{14}\right)$

$a(b-c)=-\dfrac{68}{35}\right)$

Taking right hand side, we get

$ab-ac=1.6\times \dfrac{1}{-2}-1.6\times \dfrac{-5}{-7}$

$ab-ac=-\dfrac{16}{20}-\dfrac{8}{7}$

$ab-ac=-\dfrac{4}{5}-\dfrac{8}{7}$

Taking LCM, we get

$ab-ac=\dfrac{-28-40}{35}$

$ab-ac=\dfrac{-68}{35}$

Now,

$LHS=RHS$

Hence proved.

7 0

2 years ago

PLEASEE HELPPPP MEEE

andrew11 [14]

Here hope this helpssssss

7 0

2 years ago

Marcellus has a pitcher that contained 5/8 gallon limeade. Marcellus drank 1/4 gallon of the limeade, and Marcy drank 1/8 gallon

mash [69]

Answer:

2/5

Step-by-step explanation:

Given Marcellus drank 1/4 gallon of the limeade and Marcy drank 1/8 gallon of the limeade

Given that only 5/8 portion of the pitcher contains limeade

Total amount drunk = amount drunk by Marcellus + amount drunk by Marcy

Total amount drunk = $\frac{1}{4} +\frac{1}{8}$ = $\frac{3}{8}$

The amount of Limeade remained = The amount initially - the amount drunk

The amount remained = $\frac{5}{8} -\frac{3}{8}$ = $\frac{1}{4}$

Fractional part = amount remained / amount initially = $\frac{\frac{1}{4} }{\frac{5}{8} }$ = $\frac{2}{5}$

8 0

2 years ago

Can anyone help me with this and explain it too?

arlik [135]

Answer:

(6, 3)

Step-by-step explanation:

$Midpoint (x_{m},y_{m})=(\frac{x_A + x_B}{2}, \frac{y_A + y_B}{2})\\\\=(\frac{3 + 9}{2}, \frac{6 + 0}{2})\\\\=(\frac{12}{2}, \frac{6}{2})\\\\Midpoint of a line segment (x_M, y_M) = (6, 3)$

How to Calculate Midpoint?

The x-coordinate of the midpoint M of the segment $\overline{AB}$ is the arithmetic mean of the x-coordinates of the endpoints of the segment $\overline{AB}$ . Similarly, the y-coordinate of the midpoint M of the segment $\overline{AB}$ is the arithmetic mean of the y-coordinates of the endpoints of the segment $\overline{AB}$ .

7 0

3 years ago