Answer: fluffy is 11 years old
Scuffy is 8 years old
Step-by-step explanation:
Let x represent the present age of Fluffy the cat.
Let y represent the present age of Scuffy the dog.
Fluffy the cat is 3 years older than Scuffy the dog. This means that
x = y + 3 - - - - - -- - - - - 1
Six less than five times Scruffy's age is one more than three times Fluffy's age. This means that
5y - 6 = 3x + 1
5y - 3x = 1 + 6
5y - 3x = 7 - - - - - - - - - -2
Substituting equation 1 into equation 2, it becomes
5y - 3(y + 3) = 7
5y - 3y - 9 = 7
5y - 3y = 7 + 9
2y = 16
y = 16/2 = 8
x = y + 3
x = 8 + 3 = 11
1.)-2v-7=-23
-2v=-16
v=8
2.)x/3-10=-12
x/3-10=-12
x/3=-2
x=-6
3.) x/4+10=14
x/4=4
x=16
Answer: C. 18.8w
Step-by-step explanation:
Since Toby exercise 14hours a week, and John exercises 20% more than Toby
John increment in number of hours compared to Tobi will be;
20/100 ×14 = 2.8hrs
This shows John exercises 2.8hrs more than Tobi. Total number of hours exercised by John will become;
14+2.8 = 16.8hrs
Since Jenny exercises two more hours than John, Total number of hours exercised by Jenny will be;
16.8hrs+2hrs
= 18.8hrs/week
If Jenny exercise 18.8hrs in a week, it means she will exercise 18.8×w/1 in w weeks which gives 18.8w weeks.
Answer:
0.3891 = 38.91% probability that only one is a second
Step-by-step explanation:
For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
17% of its goblets have cosmetic flaws and must be classified as "seconds."
This means that 
Among seven randomly selected goblets, how likely is it that only one is a second
This is P(X = 1) when n = 7. So
0.3891 = 38.91% probability that only one is a second
Answer:
yes
Step-by-step explanation:
