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loris [4]
3 years ago
9

Given vectors p=2i-j q= -i+j find 1. p+q, 2. p-q, 3. 2p-3q

Mathematics
1 answer:
Romashka [77]3 years ago
8 0

Answer:

See below

Step-by-step explanation:

p=2i-j

q=-i+j

p+q=(2i-j)+(-i+j)=2i-j-i+j=i

p-q=(2i-j)-(-i+j)=2i-j+i-j=3i-2j

2p-3q=2(2i-j)-3(-i+j)=4i-2j+3i-3j=7i-5j

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Can someone explain HOW to simplify this algebraic fraction, as in tell me why and what I need to do for each step : 1-n/n^2-1
Andreyy89

- I’m assuming the expression implies the following:

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The steps goes as follows:

= -(n-1)/(n^2-1) (factored a negative out)
= -(n-1)/[(n+1)(n-1)] (Factored denominator into a difference of squares, but don’t just blindly accept the fact, expand it and you should get the original denominator)

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8 0
3 years ago
The expression 6+16k factored using the GCF is what???????
tatiyna

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given : 6+16k

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