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3 years ago

Px^2-qx+r=0 solve by complete squaring method

Mathematics

1 answer:

Natasha2012 [34]3 years ago

3 0

Step-by-step explanation:

px^2-qx+r

p(x^2-q/px)+r

p[(x^2-q/px +(q/2p)^2_(q/2p)^2)]+r

p[(x-q/2p)^2 -q^2/4p^2)]+r

p(x-q/2p)^2 -q^/4p+r

p(x-q/2p)^2-(q^2-4pr)/4p

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erma4kov [3.2K]

Answer:

therefore the value of V=-6

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3 years ago

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tigry1 [53]

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3 years ago

A delivery truck is transporting boxes of two size: the combined weight of a large box and a small box is 65 pounds. The truck i

Bas_tet [7]

pretty much about the same as before.

a = weight of a large box

b = weight of a small box.

we know their combined weight is 65 lbs, thus a + b = 65.

we also know that the truck has 60 large ones, and 55 small ones, thus 60*a is the total weight for the large ones and 55*b is the total weight for the small ones, and we know that is a total of 3775, 60a + 55b = 3775.

$\bf \begin{cases} a+b=65\\ \boxed{b}=65-a\\ \cline{1-1} 60a+55b=3775 \end{cases}\qquad \qquad \stackrel{\textit{substituting on the 2nd equation}}{60a+55\left( \boxed{65-a} \right)=3775} \\\\\\ 60a+3575-55a=3775\implies 5a+3575=3775\implies 5a=200 \\\\\\ a=\cfrac{200}{5}\implies \blacktriangleright a = 40 \blacktriangleleft \\\\\\ \stackrel{\textit{since we know that}}{b=65-a\implies }b=65-40\implies \blacktriangleright b=25\blacktriangleleft$

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4 years ago

Express the fractions 1/2, 3/16, and 7/8 with an LCDA.8/16 3/16 14/16B. 1/4 3/4 7/4C. 1/32 3/32 732D. 4/8 6/8 14/8

NISA [10]

The least (or lowest) common denominator of 3, 16 and 8 is 16. That already points us to answer A.

Checking for each fraction:

1/2 * 8/8 = 8/16
3/16 * 1/1 = 3/16
7/8 * 2/2 = 14/16

Yep. Answer A.

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3 years ago

Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

AlexFokin [52]

Answer:

AE = 60 units

Step-by-step explanation:

GE is one third the length of AE so...

GE = 1/3(AE)

20 = 1/3x

3(20) = (1/3x)3/1

60 = x

x = 60

AE = 60 units

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3 years ago

Px^2-qx+r=0 solve by complete squaring method​

Px^2-qx+r=0 solve by complete squaring method