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2 years ago

Dentify the type of transformation in the following graphic and describe the change.

Mathematics

1 answer:

zalisa [80]2 years ago

4 0

Answer:

Translation, five units to the left

Step-by-step explanation:

Point A is moved to the left to become A'.

Similarly, Points M, H, and T have moved to the left to become M', H', and T', respectively.

This type of transformation, in which all the points in a figure move in the same direction and by the same amount, is called a translation (moving sideways).

Each point has moved five units to the left.

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Give the equation of the line through the point (4, 5) with a slope of - 9/2

kodGreya [7K]

Answer:

Step-by-step explanation:

y - y1 = m(x - x1)

y - 5 = -9/2*(x - 4)

y -5 = -9/2x + 9*4/2

y - 5 = -9x/2 +9*2

y-5=-9x/2 + 18

y= -9x/2 + 18 +5

y= -9x/2 + 23 {y =mx+c}

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3 years ago

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37 35 Х x = What’s the answer?

Ainat [17]

Answer:

Step-by-step explanation:

use Pythagorean theorem

37^2 = 35^2 + x^2

x= ± $\sqrt[2]{37^2-35^2}$

x1 = 12

x2= -12 but it is illogical as length cannot be negative

answer: x = 12

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3 years ago

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You want to order some shirts that cost 14 dollars each shipping is 7 dollars per order if you buy 11 tshirts what will the orde

jolli1 [7]

11*14 = 154

154+7 = $161

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3 years ago

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What fraction of a circle is 80°?

Liono4ka [1.6K]

Answer:

2/9

Step-by-step explanation:

Simplify 80°/360°

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3 years ago

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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

8 0

3 years ago