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yarga [219]
2 years ago
14

WILL GIVE BRAINLIEST

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
8 0

Answer:

It has no solution because, 14x cancels out -14x when you move the variables to the left and leaves the equation as 0 = -12, however we know that 0 does not equal -12 which means this solution is false; therefore this equation has no solution since 0 does not equal -12.

Step-by-step explanation:

5 - 4x - 7 - 10x = -8x - 4 - 6x - 10 (Given)

-2 - 14x = -14x - 14 (Combine like terms)

0 = -12 (Move variables(x) to the left and the constants to the right)

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Katen [24]
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8 0
3 years ago
2sec^2x - secx - 1 = 0
Ivenika [448]
What are you trying to do here?
Solve the graph, or make it appear as something else?

First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0

sec (x) (2sec (x) -2) = 0


Then we're going to separate the two to find the zeros of each because anything time 0 is zero.

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Now, let's simplify the second one as the first one is already.

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I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
8 0
3 years ago
Whats the equation 2+2 yo
anyanavicka [17]
Sheesh I think is 4 :)
4 0
3 years ago
Read 2 more answers
What is the solution to |x – 5| + 2 < 20?
stepladder [879]

Answer:

Step-by-step explanation:

hello :

|x – 5| + 2 < 20  means :  |x – 5| + 2-2 < 20-2

|x – 5|  < 18

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-18+5< x - 5+5 < 18+5

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3 0
2 years ago
HELP ME!!!<br> What is 1x0=???<br> (I honestly dunno ._.)
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Answer:

good one

Step-by-step explanation:

6 0
3 years ago
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