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Vlada [557]
3 years ago
13

Help needed I’m not good at geometry

Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0

Answer:

I think it's 19.21, but in your case it would be 19.2. Sorry if I'm wrong

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Write a quadratic function in vertex form whose graph has the vertex (1, 0) and passes through the point (2, −17).
Brilliant_brown [7]

Answer:

x^4 +y+1

Step-by-step explanation:

6 0
3 years ago
How do i solve divide 5/8 by 50%
Ede4ka [16]
50% is \frac{50}{100}
We have two ways to do this, pick your favor:
either by fractions:
\frac{5}{8} ÷ \frac{1}{2}
(\frac{50}{100} =  \frac{1}{2}
Multiply by the reciprocal of \frac{1}{2} which is 2(flip it)

\frac{5}{8} × 2 = \frac{5}{4} = 1.25

Or change them to decimals:
\frac{5}{8} = 0.625
\frac{50}{100} = 0.5

0.625 ÷ 0.5

0.5 I 0.625
multiply by 10 to make it easier to divide(it still gives us the same answer)
0.5 × 10 = 5
0.625 × 10 = 6.25
     1.25
5 I 6.25
    -5
     12
    -10
       25
      -25
         0

0.625 ÷ 0.5 = 1.25

7 0
2 years ago
When planning road development, the road commission estimates the future population using the function represented in the table,
Sindrei [870]

The significance of 160,000 in the function is the initial population at the time of the estimation.

The correct option is (C)

<h3>What is data?</h3>

A collection of facts, such as numbers, words, measurements, observations or even just descriptions of things.

Given:

As per the table attached below:

F(x) signify the total population when the time was x hour.

So,  160,000 in the function signifies that the population at starting i.e., initial point.

Learn more about this concept here:

brainly.com/question/17112729

#SPJ1

7 0
2 years ago
For the values a=8 which is a leg of a right triangle and value c=19 which is the hypotenuse find the length of the other leg b
FinnZ [79.3K]
C^2=a^2+b^2  we are given the hypotenuse of 19 units and one leg of 8 units so:

19^2=8^2+b^2

361=64+b^2

b^2=297

b=√297

b≈17.2 to the nearest tenth


4 0
3 years ago
Read 2 more answers
The prices of all college textbooks follow a bell-shaped distribution with a mean of $113 and a standard deviation of $12. Using
Soloha48 [4]

Step-by-step explanation:

In statistics, the empirical rule states that for a normally distributed random variable,

  • 68.27% of the data lies within one standard deviation of the mean.

  • 95.45% of the data lies within two standard deviations of the mean.

  • 99.73% of the data lies within three standard deviations of the mean.

In mathematical notation, as shown in the figure below (for a standard normal distribution), the empirical rule is described as

                             \Phi(\mu \ - \ \sigma \ \leq X \ \leq \mu \ + \ \sigma) \ = \ 0.6827 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi(\mu \ - \ 2\sigma \ \leq X \ \leq \mu \ + \ 2\sigma) \ = \ 0.9545 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi}(\mu \ - \ 3\sigma \ \leq X \ \leq \mu \ + \ 3\sigma) \ = \ 0.9973 \qquad (4 \ \text{s.f.})

where the symbol \Phi (the uppercase greek alphabet phi) is the cumulative density function of the normal distribution, \mu is the mean and \sigma is the standard deviation of the normal distribution defined as N(\mu, \ \sigma).

According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution N(113, \ 12),

                \Phi(113 \ - \ 3 \ \times \ 12 \ \leq \ X \ \leq \ 113 \ + \ 3 \ \times \ 12) \ = \ 0.9973 \\ \\ \\ \-\hspace{1.75cm} \Phi(113 \ - \ 36 \ \leq \ X \ \leq \ 113 \ + \ 36) \ = \ 0.9973 \\ \\ \\ \-\hspace{3.95cm} \Phi(77 \ \leq \ X \ \leq \ 149) \ = \ 0.9973

Therefore, the price of 99.7% of college textbooks falls inclusively between $77 and $149.

5 0
2 years ago
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