All categories

2 years ago

TWO jets leave an air base at the same time and travel in opposite directions. One jet travels 91

Mathematics

1 answer:

iren [92.7K]2 years ago

7 0

Answer:

Step-by-step explanation:

distance = rate*time

d=r*t

d=(r-83)*5

6005 = r*5+(r-83)*5

6005 = 5r + 5r - 415

6005 = 10r - 415

6005 + 415 = 10r

6420 = 10r

r = 6420/10

r = 642 mph for the faster jet

r - 83 = 642 - 83 = 559 mph for the slower jet

Hope this helps!

You might be interested in

If f(x) = x + 5, what does f(8) represent?

wel

All you do is plug in 8 for x.

So it f(8) = 8 + 5
which equals 13

Hope this helps!

8 0

3 years ago

Read 2 more answers

Can someone help me with this

Zielflug [23.3K]

Sure jejshehhdjsjshdhdhdjsjdjdjd

4 0

3 years ago

Read 2 more answers

Find the area of the part of the paraboloid z = 9 - x^2 - y^2 that lies above the xy-plane.

svetoff [14.1K]

Parameterize this surface (call it $S$ ) by

$\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(9-u^2)\,\vec k$

with $0\le u\le3$ and $0\le v\le2\pi$ . Take the normal vector to $S$ to be

$\vec r_u\times\vec r_v=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k$

Then the area of $S$ is

$\displaystyle\iint_S\mathrm dA=\iint_S\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^3u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv$

$=\displaystyle2\pi\int_0^3u\sqrt{1+4u^2}\,\mathrm du=\boxed{\frac{37\sqrt{37}-1}6\pi}$

3 0

4 years ago

What's the difference between 1,968 and 3,000? Check your answer using inverse operations.

Leto [7]

Using subtraction, you would take 3,000 and subtract 1968 from it to leave you 1,032. With that number, the answer to your question is "C"

5 0

4 years ago

Read 2 more answers

Wendy paints a wall that is 10.5 feet tall and 9.2 feet wide what is the area of the wall that she painted?

tamaranim1 [39]

Area is length times width.

So you need to do:

10.5 x 9.2 = 96.6

The area of the wall is 96.6 feet square.

5 0

4 years ago