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SpyIntel [72]
3 years ago
9

Which number, when rounded to the nearest whole number and to the nearest tenth, rounds to the same value?

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0
04.95 is the answer to this question.
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Peter is working for an hourly wage of $12 if you worked for 20 hours last week was his gross pay
klemol [59]
You would take 12 X 20, and that equals 240.  $120 is your answer.
4 0
4 years ago
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What is 4.024 as a mixed fraction
Ainat [17]

Answer:

4 3/125

Step-by-step explanation:

You can ignore the 4 for now and find what .024 is as a fraction. (3/125)

Then put your 2 answers together.

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3 years ago
An article written for a magazine claims that 78% of the magazine's subscribers report eating healthily the previous day. Suppos
Schach [20]

Answer:

89.44% probability that less than 80% of the sample would report eating healthily the previous day

Step-by-step explanation:

We use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.78, n = 675

So

\mu = E(X) = np = 675*0.78 = 526.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{675*0.78*0.22} = 10.76

What is the approximate probability that less than 80% of the sample would report eating healthily the previous day?

This is the pvalue of Z when X = 0.8*675 = 540. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{540 - 526.5}{10.76}

Z = 1.25

Z = 1.25 has a pvalue of 0.8944

89.44% probability that less than 80% of the sample would report eating healthily the previous day

8 0
4 years ago
Linear functions are hard (._.)
Pani-rosa [81]

I know right

Step-by-step explanation:

7 0
3 years ago
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A bag has 4 red marbles, 5 white marbles, and 6 blue marbles. three marbles are drawn from the bag (without replacement). what i
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It was 1/3 because all colour could be same
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