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3241004551 [841]
2 years ago
11

Steven has $10. Each week he earns $2.

Mathematics
2 answers:
podryga [215]2 years ago
8 0

Answer:

(a) 2*10 = 20

10+20=30

(b) ceil((25-10)/2) = 8

My name is Ann [436]2 years ago
6 0

Answer:

$30 at the end of 10 weeks

7.5 weeks, or 8 (rounded)

Step-by-step explanation:

10*2=20

10+20=30

10+2x=25

2x=25-10

2x=15

x=7.5

7.5 weeks, or 8 (rounded)

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arsen [322]

Answer:

option-A

\frac{x^4+3x^3-2x^2+4}{x-2}=x^3+5x^2+8x+16+\frac{36}{x-2}

Step-by-step explanation:

we are given

divisor is

=x^4+3x^3-2x^2+4

Dividend is

=x-2

so, we can use synthetic division

so, we can write our expression as

\frac{x^4+3x^3-2x^2+4}{x-2}=x^3+5x^2+8x+16+\frac{36}{x-2}

so,

option-A

5 0
3 years ago
X=−4a 2 +3ab+12b 2 Y=9a 2 +ab−7b 2 ​ Y+X=Y+X=Y, plus, X, equals
dimaraw [331]

Answer:

5a  

2

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Step-by-step explanation:

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6 0
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Let a and b be real numbers satisfying a^3 - 3ab^2 = 47 and b^3 - 3a^2 b = 52. Find a^2 + b^2.
boyakko [2]

Answer: a²+b² = -99/2

Step-by-step explanation:

Since we are given two equations, this equations will be solved simultaneously to get a² and b²

a³ - 3ab² = 47 ... 1

b³ - 3a² b = 52... 2

From 1, a(a² - 3b²) = 47...3

From 2, b(b² - 3a²) = 52... 4

Adding 3 and 4, we have;

a²+b²-3b²-3a² = 99 (note that a and b will no longer be part of the equations as they have been factored out)

a²+b²-(3b²+3a²) = 99

(a²+b²) -3(b²+a²)= 99

Taking the difference we have

- 2(a²+b²) = 99

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8 0
3 years ago
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Answer:

Step-by-step explanation:

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