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3 years ago

Can someone please help me figure out this problem. just figure out what 1,2, and 3

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

4 0

1 is 39. J don’t know about 2 and 3 though:(

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What three consecutive even integers have a sum of 78

Airida [17]

Answer:

24,26,28

Step-by-step explanation:

78 divided by 3 is 26, which means that 26 is the middle number and the next even number that is lower and bigger are the other two integers. You divide it by 3 because it's 3 consecutive even intergers

8 0

3 years ago

Determine the area (in units2) of the region between the two curves by integrating over the x-axis. y = x2 − 24 and y = 1

astra-53 [7]

Answer:

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

Step-by-step explanation:

This case represents a definite integral, in which lower and upper limits are needed, which corresponds to the points where both intersect each other. That is:

$x^{2} - 24 = 1$

Given that resulting expression is a second order polynomial of the form $x^{2} - a^{2}$ , there are two real and distinct solutions. Roots of the expression are:

$x_{1} = -5$ and $x_{2} = 5$ .

Now, it is also required to determine which part of the interval $(x_{1}, x_{2})$ is equal to a number greater than zero (positive). That is:

$x^{2} - 24 > 0$

$x^{2} > 24$

$x < -4.899$ and $x > 4.899$ .

Therefore, exists two sub-intervals: $[-5, -4.899]$ and $\left[4.899,5\right]$ . Besides, $x^{2} - 24 > y = 1$ in each sub-interval. The definite integral of the region between the two curves over the x-axis is:

$A = \int\limits^{-4.899}_{-5} [{1 - (x^{2}-24)]} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} [{1 - (x^{2}-24)]} \, dx$

$A = \int\limits^{-4.899}_{-5} {25-x^{2}} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} {25-x^{2}} \, dx$

$A = 25\cdot x \right \left|\limits_{-5}^{-4.899} -\frac{1}{3}\cdot x^{3}\left|\limits_{-5}^{-4.899} + x\left|\limits_{-4.899}^{4.899} + 25\cdot x \right \left|\limits_{4.899}^{5} -\frac{1}{3}\cdot x^{3}\left|\limits_{4.899}^{5}$

$A = 2.525 -2.474+9.798 + 2.525 - 2.474$

$A = 9.9\,units^{2}$

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

4 0

3 years ago

Find the value of z. A. 25.25 B. 76.25 C. 51 D. 129

avanturin [10]

Answer:

25.25

Step-by-step explanation:

Angle Formed by Two Chords= 1/2(SUM of Intercepted Arcs)

The angle formed by the two chords is (180 -x)

We need to find x first

x = 1/2 (54+204)

x = 129

The angle formed by the two chords is (180 -129) = 51

51 = 1/2 ( z+3z+1)

Multiply by 2

102 = 4z+1

101 = 4x

Divide by 4

101/4 = z

25.25 =z

5 0

3 years ago

X+3y=5 -2x-6y=-10 Solve using elimination

RSB [31]

Slimination
multiply first equaiton by 2
2x+6y=10
add to second equiaotn
2x-2x+6y-6y=10-10
0=0
this is true so therfor they are the same equaiton

so solve
x+3y=5
3y=-x+5
y=-1/3x+5/3

subsituter values for x and get valuse for y

if x=2 then y=1

3 0

4 years ago

Over a 3.5 year period, 27.5 inches of snow fell in Jackson City. What was the average yearly snowfall in Jackson Cit

Ilya [14]

27.5 / 3.5 = 7.86; The average yearly snowfall was 7.86 inches.

7 0

3 years ago